Answer:
m ∠JPN = 131°
Step-by-step explanation:
m ∠JPL = m ∠MPK Vertical angles are =
7x + 19 = 11x -17 Substitution
- 4x = -36 Algebra: Solving for x
x = 9 Algebra: Solving for x
m ∠JPL = 82° Substitution x = 9 into m ∠JPL = 7x +19
m ∠JPL + m ∠LPK = 180° Definition of linear pair/supplement
angles = 180°
82° + m ∠LPK = 180° Substitution
m ∠LPK = 98° Algebra
m ∠LPK = m ∠LPN + m ∠NPK Angle addition Theorem
PN bisects ∠LPK Given
m ∠LPN = m ∠NPK Definition of angle bisector
98 ° = 2 ( m ∠LPN) Substitution
m ∠LPN = 49° Algebra
m ∠JPN = m ∠JPL + m ∠LPN Angle Addition
m ∠JPN = 82° + 49° Substitution
m ∠JPN = 131° Addition
y + 3 = (x - 5)
the equation of a line in point- slope form is
y - b = m ( x - a )
where m is the slope and (a, b) a point on the line
here m = and (a,b) = (5 , - 3 )
y + 3 = (x - 5 ) ← in point-slope form
Well first of all you got to show your answer.
Answer:
The correct answers are x + y = 5600 and x - y = 700.
Step-by-step explanation:
Write a system of equations in x and y describing the situation. Do not solve the system.
Keiko has a total of $ 5600, which she has invested in two accounts.
Let x be the amount of money in the larger account and y be the amount of money in the smaller account.
So, Keiko has invested her $5600 in two accounts x and y.
Thus x + y = 5600.
Also, given by the problem, the larger account (x) is $ 700 greater than the smaller account (y).
Thus x - y = 700.
Thus the two system of equation in x and y describing the given situation are
x + y = 5600 and x - y = 700
It is greater than 1
I hope this helps! I'm also more than happy to elaborate if you want :)