5 and 6 is 65 and 3 and 2 is 25 so I would say add 65 and 25
-4p^2 - 9p + 2 ezzzzzzz just switch the signs bruhhhh
The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.
1 hour: $7
2 hours: $7 + $5 = 7 + 5 * 1 = 12
3 hours: $7 + $5 + $5 = 7 + 5 * 2 = 17
4 hours: $7 + $5 + $5 + $5 = 7 + 5 * 3 = 22
Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.
Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.
The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.
C(x) = 7 + 5(x - 1)
This can be left as it is, or it can be simplified as
C(x) = 7 + 5x - 5
C(x) = 5x + 2
Answer: C(x) = 5x + 2
Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
Answer:
1
Step-by-step explanation:
The product of any nonzero real number and its multiplicative inverse (reciprocal) is always 1. This is called the multiplicative identity or the identity element of multiplication.
~Hope this helps!~
Answer:
W = 2 cm
L = 5 cm
Step-by-step explanation:
A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. Its area, the amount of space inside it, can be found using the formula A = l*w. If the area is 10 cm² and the length is "3 cm less than 4 times the width" or 4w - 3, you can substitute and solve for w.
A = l*w
10 = (4w - 3)(w)
10 = 4w² - 3w
Subtract 10 from both sides to make the equation equal to 0. Then solve the quadratic by quadratic formula.
4w² - 3w - 10 = 0
Substitute a = 4, b = -3 and c = -10.
There are two possible solutions which can be found.
3 + 13 / 8 = 16/ 8 = 2
3 - 13 / 8 = -10/8 = -5/4
Since w is a side length or distance, it must be positive so w = 2 cm.
If the width is 2 cm then the length is 4(2) - 3 = 8 - 3 = 5 cm.
