OKAY, so I'm going to start with Q2 (not 100% sure how to work out 1, but lets use process of elimination). Firstly, the rule is y=mx+c So, start with the first line y=2x-3, from this the first thing you need to do is find the y-intercept (m) and the gradient (c). So, this is very simple 2 is m and -3 is c (if you look at the rule it matches up). m=2/1(this is rise/run, rise is how much you go up by, and run is how much you go left or right by (left if positive, right if negative)) c=-3 Now, go to your graph, and look on the y line and go to -3. Then go left, 1, and up 2. IS THERE A LINE CROSSING THROUGH THIS POINT? Yes? Good. Now for y=-1/2+1. Looking at the rule again (y=mx+c), m=-1/2 (rise/run) c=1 NOW, once again go to your graph, and look on the y line and go to 1 (in this case the line actually passes through this point), now go right 2 places and up 1. IS THERE A LINE? Yes? Good!
NOOOW, for Q3, use the same steps and you will have the answer. y=1/4x-2 m=1/4 (rise/run) c=-2 Look at graph C, start at -2 on the y line, go left 4, and up 1? Yes? Line crossing through this point? good!! Now for the 2nd one, y= -2/5x+4 m=-2/3 c=4 Look at the same graph start at 4 on the y line, go right 5 and up 2! Got it? There's a line crossing through this point, yes? YAY
Now I have no idea how to do Q1, but by process of elimination it's pretty obvious. I hope this is right! Okay, bye!! :D
James should define that the rays must be collinear. the two rays coming from the same point will form collinear rays which will form an angle at end point.
The statement of james should be precise in order to clearly explain the angle formation.
The two non collinear rays will form an angle at end point where they meet with each other.
The defined vertex will form the appropriate angle. there should be defined term for the non collinear rays.
