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sammy [17]
2 years ago
8

HELP PLEASE NEED BEFORE TOMORROW MORNING

Mathematics
1 answer:
9966 [12]2 years ago
5 0
Okay YAS, I loove linear equations... moving on. 

OKAY, so I'm going to start with Q2 (not 100% sure how to work out 1, but lets use process of elimination). Firstly, the rule is y=mx+c So, start with the first line y=2x-3, from this the first thing you need to do is find the y-intercept (m) and the gradient (c). So, this is very simple 2 is m and -3 is c (if you look at the rule it matches up). 
m=2/1(this is rise/run, rise is how much you go up by, and run is how much you go left or right by (left if positive, right if negative))
c=-3
Now, go to your graph, and look on the y line and go to -3. Then go left, 1, and up 2. IS THERE A LINE CROSSING THROUGH THIS POINT? Yes? Good. 
Now for y=-1/2+1. Looking at the rule again (y=mx+c), 
m=-1/2 (rise/run)
c=1
NOW, once again go to your graph, and look on the y line and go to 1 (in this case the line actually passes through this point), now go right 2 places and up 1. IS THERE A LINE? Yes? Good!

NOOOW, for Q3, use the same steps and you will have the answer. 
y=1/4x-2
m=1/4 (rise/run)
c=-2
Look at graph C, start at -2 on the y line, go left 4, and up 1? Yes? Line crossing through this point? good!!
Now for the 2nd one, 
y= -2/5x+4
m=-2/3
c=4
Look at the same graph start at 4 on the y line, go right 5 and up 2! Got it? There's a line crossing through this point, yes? YAY

Now I have no idea how to do Q1, but by process of elimination it's pretty obvious. I hope this is right! Okay, bye!! :D
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yan [13]

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because sin theta = height / hupotaneous

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Luba_88 [7]
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4 0
3 years ago
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ANEK [815]

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