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3 years ago

3) Artemis has 6 boards cut in various lengths as shown. She wants to use 3 of them to frame

Mathematics

1 answer:

lora16 [44]3 years ago

6 0

Answer:

It's either 3 Triangles

, 4 Triangles

, 5 Triangles

, or 6 Triangles

Step-by-step explanation:

Considering how many answers there are, there's a 1/4 chance for it to be any. Concluding by that it's either 3 Triangles

, 4 Triangles

, 5 Triangles

, or 6 Triangles

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in 15 years Pam hope to have $30,000to make a down payment on a house. how much would she need to invest right now in a mutual f

Goryan [66]

Answer:

She needs to invest $13,636.36 right now

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

$T = E + P$

In this question:

In 15 years, so $t = 15$

She wants to have $30,000, so $T = 30000$

8% interest, so $I = 0.08$

We have to find P.

$T = E + P$

$30000 = E + P$

$E = 30000 - P$

Replacing:

$E = P*I*t$

$30000 - P = P*0.08*15$

$30000 - P = 1.2P$

$2.2P = 30000$

$P = \frac{30000}{2.2}$

$P = 13636.36$

She needs to invest $13,636.36 right now

5 0

3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

3 years ago

8. | 11 | 14 | 17 | 20<br> What’s the function

Murrr4er [49]

Answer:

What do you exactly need to do?

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Solve x: <br> 6 - 4x = -38<br> --Please help! This is homework due in for Monday! Xx

igomit [66]

Isolate the x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction)

First, subtract 6 from both sides

-4x + 6 (-6) = -38 (-6)

-4x = -38 - 6

-4x = -44

Next, fully isolate the x by dividing -4 from both sides

(-4x)/-4 = (-44)/-4

x = -44/-4

x = 11

11 is your answer for x.

5 0

3 years ago

Read 2 more answers

Wich function is described by the value in the table

kolbaska11 [484]

The table isn’t shown so I cant tell

3 0

3 years ago