The slope of the line, is the one with an variable, in this case x. The other value, 27.52, is the y intercept, which would represent how much money he began with. So the variable 17.63x represents how much he could expect to make per week. We know it is per week because there is only a single x, if there were two x's it would be per 2 weeks, three x's per 3 weeks and so on.
From this we can conclude the answer is B, Aidan can expect to save about $17.63 each week
Answer with Step-by-step explanation:
The given differential euation is
![\frac{dy}{dx}=(y-5)(y+5)\\\\\frac{dy}{(y-5)(y+5)}=dx\\\\(\frac{A}{y-5}+\frac{B}{y+5})dy=dx\\\\\frac{1}{100}\cdot (\frac{10}{y-5}-\frac{10}{y+5})dy=dx\\\\\frac{1}{100}\cdot \int (\frac{10}{y-5}-\frac{10}{y+5})dy=\int dx\\\\10[ln(y-5)-ln(y+5)]=100x+10c\\\\ln(\frac{y-5}{y+5})=10x+c\\\\\frac{y-5}{y+5}=ke^{10x}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%28y-5%29%28y%2B5%29%5C%5C%5C%5C%5Cfrac%7Bdy%7D%7B%28y-5%29%28y%2B5%29%7D%3Ddx%5C%5C%5C%5C%28%5Cfrac%7BA%7D%7By-5%7D%2B%5Cfrac%7BB%7D%7By%2B5%7D%29dy%3Ddx%5C%5C%5C%5C%5Cfrac%7B1%7D%7B100%7D%5Ccdot%20%28%5Cfrac%7B10%7D%7By-5%7D-%5Cfrac%7B10%7D%7By%2B5%7D%29dy%3Ddx%5C%5C%5C%5C%5Cfrac%7B1%7D%7B100%7D%5Ccdot%20%5Cint%20%28%5Cfrac%7B10%7D%7By-5%7D-%5Cfrac%7B10%7D%7By%2B5%7D%29dy%3D%5Cint%20dx%5C%5C%5C%5C10%5Bln%28y-5%29-ln%28y%2B5%29%5D%3D100x%2B10c%5C%5C%5C%5Cln%28%5Cfrac%7By-5%7D%7By%2B5%7D%29%3D10x%2Bc%5C%5C%5C%5C%5Cfrac%7By-5%7D%7By%2B5%7D%3Dke%5E%7B10x%7D)
where
'k' is constant of integration whose value is obtained by the given condition that y(2)=0\\
Thus the solution of the differential becomes
Answer:
8/9 sorry if wrong
Step-by-step explanation:
4/16, 5/20, 6/24, 7/28, 8/32...
Answer:
C
Step-by-step explanation:
