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Artemon [7]
2 years ago
10

All of the following fractions are equal to

Mathematics
2 answers:
Studentka2010 [4]2 years ago
8 0

Answer:

Except 4 out of 6

the answer is the third one

BabaBlast [244]2 years ago
4 0
The third one is not 1/2
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The temperature was -5 ℉ in Denver and then fell 8 ℉ by the morning.<br> Answer now please
allochka39001 [22]

Answer:

it was -5 and then it fell 8 degrees

-5 -8 = -13 degrees F

Step-by-step explanation:

8 0
3 years ago
Please help me solve this
andrew-mc [135]

A function assigns the values. The value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given p(x)= x²+5x, therefore, the value of (p·p)(x) can be written as,

(p·p)(x) = p(p(x))

            = (x²+5x)²+5(x²+5x)

            = x⁴ + 25x² + 10x³ + 5x² + 25x

            = x⁴ + 10x³ + 30x² + 25x

Hence, the value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

4 0
2 years ago
At an amusement park, 10 out of 25 tickets sold were discount tickets. What percentage of the tickets were discount ticket
mezya [45]

Answer:

<h2>40% of the tickets were discount ticket</h2>

Step-by-step explanation:

10/25 are discount tickets

x by 4 to make the denominator 100

40/100

make into percentage

40%

7 0
2 years ago
3) Suppose Sandra makes credit card purchase for $4,000 that compounds interest daily. The APR is 3%. How much interest is earne
Softa [21]

Answer:

$121.81

Step-by-step explanation:

A=  4000(1+.03/365)^365

4000\left(1+\frac{0.03}{365}\right)^{365}=4121.81305\dots

4 0
3 years ago
How many pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix
Tanzania [10]
\bf \begin{array}{lccclll}&#10;&amount&price&\textit{total price}\\&#10;&-----&-----&-----\\&#10;\textit{nuts \$1.10/lb}&x&1.10&1.10x\\&#10;\textit{candy \$1.60/lb}&36&1.6&57.6\\&#10;-----&-----&-----&-----\\&#10;\textit{mixture \$1.50/lb}&y&1.50&1.50y&#10;\end{array}

so... whatever "x" may be, we know that the whole mix will be "y" amount, thus x + 36 = y

and their total prices will also add up to 1.50y
thus  1.10x + 57.6 = 1.50y

thus     \bf \begin{cases}&#10;x+36=\boxed{y}\\&#10;1.10x+57.6=1.50y\\&#10;----------\\&#10;1.10x+57.6=1.50\left( \boxed{x+36} \right)&#10;\end{cases}

solve for "x", to see how much nuts will be added

what about "y"? well x + 36 = y
6 0
3 years ago
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