Common Pythagorean triples include
(3, 4, 5)
(5, 12, 13)
(7, 24, 25)
(9, 40, 41)
The only Pythagorean triple that is an arithmetic sequence is (3, 4, 5), so any arithmetic sequence that is a Pythagorean triple must be a multiple of that, such as (9, 12, 15) or (15, 20, 25).
The arithmetic sequences of selections B and D are unrelated to the (3, 4, 5) triple, so cannot be Pythagorean triples. For selection A, we know that 9² + 11² = 81 + 121 = 202 > 14², so that is not a right triangle.
The appropriate selection is ...
C. 7, 24, 25
The correct change would be $2.93
Hope this helps!!
12345
+ 5.6742
12350.6742 kg
1st set = 4 letters
2nd set = 4x 4 = 16 letters
3rd set = 16 x 4 = 64 letters
4th set = 64 x 4 = 256 letters
5th set = 256 x 4 = 1,024 letters
6th set =1024 x 4 = 4,096 letters
7th set = 4096 x 4 = 16,384 letters
8th set = 16,384 x 4 = 65,536 letters
Each letter cost 2
Total cost = 65,536 x 2 = 131,072
