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pentagon [3]
3 years ago
8

I’m having a little issue with my Trigonometry homework. The model of this problem does not have a number for the hypotenuse. Th

us, I concluded that the formula needed to answer this isn’t either the adjacent over hypotenuse or opposite over hypotenuse. However, when I try the formula for tangent, the answer (rounded to the nearest tenth) is 64.9. This isn’t an answer given in this worksheet. The possible answers on said sheet are 23.4 or 25.1. If someone could maybe help me out with this, that would be very appreciated!

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

9514 1404 393

Answer:

  x ≈ 23.4

Step-by-step explanation:

You are correct that the given information indicates the tangent function is appropriate.

  Tan = Opposite/Adjacent

  tan(59°) = 39/x

Multiply this equation by x/tan(59°) and you get ...

  x = 39/tan(59°)

  x ≈ 39/1.6643 ≈ 23.43

The appropriate answer choice is ...

  x = 23.4

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The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

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8 0
2 years ago
Triangles MNQ and MOP are similar. What is the slope of segment MO?
asambeis [7]

Answer:

D. 3/2

Step-by-step explanation:

The scale factor is 1/2 from OP / NQ = 1/2. Because of that, MQ is equal to half of MP and QP is equal to half of MP. Therefore, QP = MQ = 2. The slope of MO is rise over run which is 6 / 4 or 3 / 2.

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Given the line y = − 2 5 x + 3, determine if the given line is parallel, perpendicular, or neither. Select the correct answer fo
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Answer:

(a) Neither

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Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

y = -\frac{2}{5}x + 3

and

y = \frac{2}{5}x + 7

An equation written in form: y=mx + b has the slope:

m \to slope

So, in both equations:

m_1 = -\frac{2}{5}

m_2 = \frac{2}{5}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{2}{5}

For both lines to be perpendicular

m_1 * m_2 = -1

This is false in this case, because:

-\frac{2}{5} * \frac{2}{5} \ne -1

(b)

5y + 2x = -10

and

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Write equations in form: y=mx + b

5y + 2x = -10

5y = -2x +10

Divide by 5

y = -\frac{2}{5}x +2

-5x + 2y = 4

2y = 5x + 4

Divide by 2

y = \frac{5}{2}x + 2

In both equations:

m_1 = -\frac{2}{5}

m_2 = \frac{5}{2}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{5}{2}

For both lines to be perpendicular

m_1 * m_2 = -1

This is true in this case, because:

-\frac{2}{5} * \frac{5}{2} = -1

Cancel out 2 and 5

-1 = -1

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