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Alexus [3.1K]
2 years ago
8

Help me i think its add 24 to both sides

Mathematics
1 answer:
umka2103 [35]2 years ago
8 0

It is given in the question that

Steven is solving the equation

3(8-2x)+40=34

He begins with the following two steps.

Step 1: 3(8)+3(-2x)+40=34  Step 2: 24-6x+40=34

And we have to find , what will be the next step in solving the equation.

First we combine the like terms. And the like terms are 24 and 40. So we have to add 24 and 40. And that will be the next step.

So the correct option is the last option.

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The number p and 2/3 are additive inverses.
vlada-n [284]

By knowing that p and 2/3 are additive inverses, we will see that p = -2/3

So two numbers A and B are additive inverses if:

A + B = 0

Here the two numbers are p and 2/3, so we have:

2/3 + p = 0

Solving this for p gives:

p = -2/3

Then the value of p is just -2/3.

Now, I can't "drag and drop" the labels in the given image, so I will post a little graph of where each point should be:

If you want to learn more about additive inverses, you can read:

brainly.com/question/16681279

6 0
2 years ago
2. What unit of measure would you use for the volume of water in a bathtub?
JulsSmile [24]

2. You would use liters for a bathtub.

3.You would use milliliters for a medicine capsule.


7 0
2 years ago
Please solve, I have more of these to solve
earnstyle [38]

Answer:

I am trying to do the same it's so HARD

6 0
3 years ago
Write an equation for the proportional relationship shown in the table
Papessa [141]

Answer:

y =74x

Step-by-step explanation:

A proportional relationship is represented by y = kx where x is the independent variable, or input, k is the constant of proportionality, and y is the dependent variable or output.

What do we do to the values in the row for x to get the values in the row of y?

It helps to have x = 1 in this table.

74 = (k)(1)

74 = k

8 0
2 years ago
How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6​
Ivahew [28]

9\cos(2t)=6\implies\cos(2t)=\dfrac23

Using the fact that cos is 2π-periodic, we have

\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi

That is, \cos(\theta+2n\pi)=\cos\theta for any \theta and integer n.

\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi

We get 2 solutions in the interval [0, 2π] for n=0 and n=1,

t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi

4 0
2 years ago
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