Answer:
a =17.08
b = 16.97
Step-by-step explanation:
What are the values of a and b?
Using pythagoras therem';
Hyp^2 = opp^2 + adj^2
Get the value of b;
18^2 = b^2 + 6^2
324 = b^2 + 36
b^2 = 324 - 36
b^2 = 288
b = √288
b = 16.97
Get the value of a;
b^2 + 2^2 = a^2
288 + 4 = a^2
292 = a^2
a^2 = 292
a = √292
a= 17.09
Answer:
-6-b
Step-by-step explanation:
4(1-2b)+7b-10
Multiply what's in parantheses
4(1)=4
4(-2b)=-8b
4-8b+7b-10
Combine like terms
4-10 -8b+7b
-6-b
Hope this helps :)
Answer:
The period of Y increases by a factor of with respect to the period of X
Step-by-step explanation:
The equation shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared with
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of with respect to the period of X
This slope is 1/2. It goes up 1 on the y axis and over 2 on the x axis
I believe your answer is:
<span>C. Two times r equals the diameter of the circle. Pi is needed for all circle formulas, so you multiply by Pi since you are finding the circumference.
2r = d or, 2 radius = one diameter
</span>π is used in both circle equations:
<span>
2</span>πr (circumference)
πr² (area of circle)
hope this helps