The solution for this problem is:
Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
9514 1404 393
Answer:
x° = 29°
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relevant trig relationships. Here, you have the hypotenuse and the side opposite the unknown angle. So, the appropriate relation is ...
Sin = Opposite/Hypotenuse
sin(x°) = 12/25
x° = arcsin(12/25) ≈ 28.69°
The value of x is about 29.
Given:
Radius of the circle = 10 in
Central angle of the sector = 45 degrees
To find:
The area of the sector.
Solution:
Area of a sector is

Where,
is the central angle in degrees.
Putting r=10 and
, we get



Therefore, the area of the sector is 12.5π sq. inches.