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3 years ago

Please help me!!!!!!!

Mathematics

1 answer:

Pie3 years ago

7 0

Answer:

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<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u /> $\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

7 0

2 years ago

-3(-x+4)=5+3(x+1) please help

Lostsunrise [7]

Answer:

No solution.

Step-by-step explanation:

Step 1: Write equation

-3(-x + 4) = 5 + 3(x + 1)

Step 2: Solve for <em>x</em>

Distribute: 3x - 12 = 5 + 3x + 3
Combine like terms: 3x - 12 = 3x + 8
Subtract 3x on both sides: -12 ≠ 8

Here, we see that <em>x</em> has to equal no solution. No value of <em>x</em> would make the equation true.

3 0

3 years ago

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Answer the questions about the following

djyliett [7]

Answer:

10×4+1-73

40+1-73

41-73

-32

4 0

3 years ago

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Y is directly proportional to x.

djyliett [7]

Answer:

Step-by-step explanation:

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3 0

3 years ago

Write a value-returning recursive function that computes the sum of the digits in a given positive int argument. for example, if

mars1129 [50]

244556
2+4+4+5+5+6=26

5 0

3 years ago