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lapo4ka [179]
3 years ago
8

Need help!! I don't know how to solve theseeeeeeeeeeeeeeeeeeeeeeeeeeee.

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0
Cosine = adjacent/hypothenuse
Adjacent = 28
Hypothenuse = 35

Solution: 28/35
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Laura is saving money to buy a game. The game cost $36, and so far she has saved three- fourths of this cost. How much money has
Andreyy89

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Step-by-step explanation:

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3 years ago
Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.
dusya [7]

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

5 0
2 years ago
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Andrej [43]

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Step-by-step explanation:

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