Answer:
WE HAVE FIND HOW MUCH MAY TIME BIGGER IS THE VOLUME OF PYRAMID B THAN PYRAMID A.
The answer is 32 times
Step-by-step explanation:
Volume of Pyramid B = 3136 in³
Volume of Pyramid A = ?
We have to find volume of Pyramid A. As Pyramid is a square pyramid, its volume is given as:

where b = base = 7 and h = height = 6. Substitute the values:

Volume of Pyramid A = 98 in³
To find how many time B is bigger than A, divide volume of B by A:

So, volume of Pyramid B is 32 times bigger than volume of Pyramid A
The dot product will have you multiply the corresponding coordinates and add up the products
v dot w = (6*(-7)) + (7*5) + (-3*2)
v dot w = -42 + 35 - 6
v dot w = -7 - 6
v dot w = -13
Answer: -13
The answer is 2 bc I got it right on a quiz
Answer:
24 cubes
Step-by-step explanation:
You can figure this a couple of ways.
I usually find it easiest to figure in terms of the number of cubes each dimension represents. The vertical dimension (3/2 cm) is the length of 3 cubes; the front-back dimension (2 cm) is the length of 4 cubes, and the width (1 cm) is the length of 2 cubes.
The total number of cubes required is the product of the dimensions in cube-lengths: 3×4×2 = 24 cubes.
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Another way to figure this is to compute the prism volume in the given dimensions (cm³) and the cube volume in the same dimensions, then find the number of cube volumes in the prism volume.
Prism volume = l×w×h = (2 cm)(1 cm)(3/2 cm) = 3 cm³
Cube volume = (1/2 cm)³ = 1/8 cm³
Then the number of cubes that will fit in the prism is ...
(3 cm³)/(1/8 cm³) = 3×8 = 24 . . . . cubes