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ddd [48]
4 years ago
12

X + 3x= solve pleasee

Mathematics
1 answer:
makkiz [27]4 years ago
7 0

Answer:

2x

Step-by-step explanation:

x-x+3x-x

2x

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Help me with question number 6
marin [14]
Write an expression for the perimeter of each. Then set them equal and solve for w.

2(w+3) + 2w = 2(2w-5) + 2(w+1)

Is that enough info?
8 0
3 years ago
The classes at the middle school want to raise money. The sixth grade runs a bake sale for 55 hours and makes $170. The seventh
Jet001 [13]
The sixth grade runs a bake sale for 55 hours and makes $170.
So in one hour, they made 170/55 = 3.09 dollars.
Rate: $3.09/h

The seventh grade sets up a dunking booth for 44 hours and makes $112.
So in one hour, they made 112/44 = 2.54 dollars.
Rate: $2.54/h

The eight grade has a car wash and makes $192 in 66 hours.
So in one hour, they made 192/66 = 2.90 dollars.
Rate $2.90/h

3.09 > 2.90 > 2.54
So R(6th) > R(8th) > R(7th)

Which means that the sixth grade has the highest rate for raising money.

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Find x. Round your answer to the nearest tenth of a degree.<br> 25
vitfil [10]

Answer:

30

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
BRAINLIEST FOR RIGHT ANSWER!! A student wants to know how many 1 cm squares are needed to completely cover all the sides of a 10
drek231 [11]
Surface area, but there is a wrinkle which we'll talk about later.

The area is front and back top and bottom left and right, six sides in all. 

Left / Right
Area = 10 * 8 = 80 cm^2
2 Sides Area = 2 * 80 cm^2 = 160 cm^2

Top / Bottom
Area = 10 * 12 = 120
2 Side Area = 2 * 120 = 240 cm^2

Ends
Area = 8 * 12 cm = 96 cm^2 
2 sides = 2 * 96 = 192 cm^2

Total Area
The total area of all six sides is 192 + 240 + 160 = 592 cm^2

Comment and Answer
592 cm^2 <<<< Answer

There might be a problem with overlap. Right at the edge of face the gluing of the tiles stops. Do you put on one more layer or not. I would say not. You have to be told to do that. I think the question just requires a straight forward reply. If not, write me a message.  
7 0
3 years ago
Read 2 more answers
The maximum weight M that can be supported by a beam is jointly proportional to its width w and the square of its height h, and
Anettt [7]

Answer:

Step-by-step explanation:

a) The maximum weight M that can be supported by a beam is jointly proportional to its width w and the square of its height h, and inversely proportional to its length L. If k represent the constant of proportionality, the expression would be

M = kwh²/L

b) if w = 4 inches, h = 6 inches, length = 12 ft

1 foot = 12 inches

12 ft = 12 × 12 = 144 inches. Therefore

L = 144 inches

M = 4800lb

Substituting these values into

M = kwh²/L, it becomes

4800 = (k × 4 × 6²)/144

4800 = k

The equation becomes

M = 4800wh²/L

c) if L = 10ft(10 × 12 = 120 inches),

h = 10 inches

w = 3 inches, then

M = 4800 × 3 × 10²/120

M = 12000 lbs

4 0
3 years ago
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