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4 years ago

I need help plz answer !

Mathematics

1 answer:

xeze [42]4 years ago

3 0

Answer:

LETS MOM BY UR MOM

Step-by-step explanation:

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6⋅7-3^2⋅9+4^3 what is the value?

zalisa [80]

$\textsf{Hey there!}$

$\mathsf{Equation: 6 \times 7- 3^2 \times9+4^3}$

$\mathsf{3^2 = 3\times3=9}$

$\mathsf{4^3= 4\times4\times4=16\times4 = 64}$

$\mathsf{6\times7 = 42}$

$\mathsf{9\times9= 81}$

$\mathsf{New\ equation: 42 - 81 + 64}$

$\mathsf{42 -81= -39}$

$\textsf{New equation: -39 + 64}$

$\mathsf{SOLVE\ ABOVE\ \uparrow\ \& you\ will\ have\ your\ answer\ to\ this\ problem}$

$\mathsf{-39 + 64 = 25}$

$\boxed{\textsf{Thus, your answer is: \boxed{\mathsf{\bf{25}}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy day!}$

~ $\frak{LoveYourselfFirst:)}$

4 0

3 years ago

Read 2 more answers

Solve for x: 14-14x^1/3 =2

zmey [24]

Answer: 216/343 or 0.6297

Step-by-step explanation:

$14-14x^{1/3} = 2\\14 -2 = 14x^{1/3}\\12 = 14x^{1/3}\\\frac{12}{14} =x^{1/3}\\\frac{6}{7} =x^{1/3}\\(\frac{6}{7})^3 =(x^{1/3})^3\\\frac{6^3}{7^3} =x\\\\\frac{216}{343} = 0.629737609 = x$

7 0

3 years ago

The number of rainbow smelt in Lake Michigan had an average rate of change of −19.76 per year between 1990 and 2000. The bloater

mojhsa [17]

Let x = number of years between 1990 and 2000.

Rainbow smelt:
Initial population = 227
Average yearly rate of change = -19.76
The linear function that models the population is
y₁ = 227 - 19.76x

Bloater fish
Initial population = 1052
Average yearly rate of change = -92.57
The linear function that models the population is
y₂ = 1052 - 92.57x

When the two populations are equal, then y₁ = y₂.
That is
227 - 19.76x = 1052 - 92.57x
(92.57 - 19.76)x = 1052 - 227
72.81x = 825
x = 11.33 years
= 11 years, 0.33*12 months
= 11 years, 4 months
Add x to 1990 to obtain the year April 2011.

Answer:
x = 11.33 years.
This occurs in April 2001.

5 0

4 years ago

Read 2 more answers

(x^2y^3) = (xy^a)^b

Rainbow [258]

Answer:

C. $\frac{3}{2}$