I beleive the answer is B
Answer:
x = ± 4
y = - 2
Step-by-step explanation:
y = 0.5x² - 10 ------------------------(I)
y = -x² + 14 ------------------------(II)
Substitute the y value in equation (II)
0.5x² - 10 = -x² + 14 {Add x² to both sides}
0.5x² + x² -10 = 14 {combine like terms}
1.5x² - 10 = 14 {Add 10 to both sides}
1.5x² = 14 + 10
1.5x² = 24 {Divide both sides by 1.5}
1.5x²/1.5 = 24/1.5
x² = 16
x = ±4
Substitute x = 4 in (I)
y = 0.5 * 4² - 10
= 0.5*16 - 10
= 8- 10
y = -2
Substitute x = -4 in (I)
y = 0.5 * (-4)² - 10
= 0.5*16 - 10
= 8- 10
y = -2
If two events are independent, then P(A and B) = P(A) x P(B).
In your situation, you need to solve 0.185 = 0.25 x P(B).
Can you take it from there?
Answer: 46 years
Step-by-step explanation:
Let the father's age be x and the son's age be y, then 3 years ago:
Father = x - 3
son = y - 3
Then , from the first statement :
x - 3 = 3 ( y - 3 )
x - 3 = 3y - 9
x = 3y - 9 + 3
x = 3y - 6 .......................................... equation 1
In five years time
father = x + 5
son = y + 5
Then , from the second statement
x + 5 = 2 ( y + 5 )
x + 5 = 2y + 10
x = 2y + 10 - 5
x = 2y + 5 ........................ equation 2
Equating equation 1 and 2 , we have
3y -6 = 2y + 5
add 6 to both sides
3y = 2y + 5 + 6
subtract 2y from both sides
3y - 2y = 11
y = 11
substitute y = 11 into equation 1 to find the value of x
x = 3y - 6
x = 3(11) - 6
x = 33 - 6
x = 27
This means that the father is presently 27 years and the son is presently 11 years.
In four years time
father = 27 + 4 = 31
son = 11 + 4 = 15
sum of their ages in four years time will be
31 + 15 = 46 years
Shiii ion kno man why my stuff gotta be 20 letters