Answer:
8/15
Step-by-step explanation:
In a right triangle, where B is an acute angle, the tan B is equal to the measure of the side opposite B divided by the measure of the shorter side at B
tanB = 16/30 = 8/15
Answer:
there's nothing here to answer
The angle of the plane when it rose from the ground is 64.8 degrees
<h3>Application of trigonometry identity</h3>
Given the following parameters from the question
Altitude of the airplane H = 500m
Horizontal distance from airport "d" = 235
Required
angle of elevation
According to the trigonometry identity
tan x = opposite/adjacent
tan x = H/d
tan x = 500/235
tan x = 2.1277
x = arctan(2.1277)
x = 64.8 degrees
The angle of the plane when it rose from the ground is 64.8 degrees
Learn more on angle of elevation here: brainly.com/question/88158
#SPJ1
We know that there are 7 days in a week, so just divide 68 ÷ 7 and you should get 9.71 which is approximately 10 weeks
The distance formula is given by:
We are given two points A and B as
A(1,1) and
B(7,-7)
so we have ,
x1 = 1 , y1=1
x2= 7 and y2=-7
Plugging these in the formula we have:
d=√(36+64)
d=√100
d=10
Answer: The distance between A(1,1) and B(7,-7) is 10