Answer:
The maximum distance traveled is 4.73 meters in 0.23 seconds.
Step-by-step explanation:
We have that the distance traveled with respect to time is given by the function,
.
Now, differentiating this function with respect to time 't', we get,
d'(t)=9.8t-2.3
Equating d'(t) by 0 gives,
9.8t - 2.3 = 0
i.e. 9.8t = 2.3
i.e. t = 0.23 seconds
Substitute this value in d'(t) gives,
d'(t) = 9.8 × 0.23 - 2.3
d'(t) = 2.254 - 2.3
d'(t) = -0.046.
As, d'(t) < 0, we get that the function has the maximum value at t = 0.23 seconds.
Thus, the maximum distance the skateboard can travel is given by,
.
i.e. 
.
i.e. 
.
i.e. .
i.e. d(t) = 4.73021
Hence, the maximum distance traveled is 4.73 meters in 0.23 seconds.
Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
<h3>
How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
Learn more about radians on:
brainly.com/question/12939121
A. Zero points of intersection
the lines are parallel
50.74
B/c 43*.18=7.74
7.74+43=50.74
hope this helps
