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olya-2409 [2.1K]
3 years ago
8

What is the greatest common factor of the polynomial -25y^3+15y^2-5y

Mathematics
1 answer:
Sonbull [250]3 years ago
4 0

Answer:

-5y

Step-by-step explanation:

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A newly hired basketball coach promised a high-paced attack that will put more points on the board than the team’s previously te
puteri [66]

Answer:

a. z = 2.00

Step-by-step explanation:

Hello!

The study variable is "Points per game of a high school team"

The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)

The hypothesis is:

H₀: μ ≤ 99

H₁: μ > 99

α: 0.01

There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.

The statistic value under the null hypothesis is:

Z= X[bar] - μ  = 101 - 99 = 2

σ/√n 6/√36

I don't have σ, but since this is an approximation I can use the value of S instead.

I hope it helps!

7 0
3 years ago
Which is a zero of the quadratic function f(x) = 16x?? + 32x - 9?
STALIN [3.7K]

Answer:

f(x) = 16x2 + 32x - 9

 

To find the "zeros", set f(x) = 0:

 

    0 = 16x2 + 32x - 9

 

The equation is solvable by factoring or by using the quadratic formula.  The factors (use the "ac" method) are:

 

    0 = (4x-1)(4x+9)

 

    x = 1/4 = 0.25 and x = -9/4 = -2.25

Step-by-step explanation:

6 0
3 years ago
Which table best represents the steps to solve the equation 8 + = 4?
aleksklad [387]
Usaully if you add a larger number with a smaller negative number you will get your answer is 8 + -4+4
5 0
4 years ago
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
( BRAINLIEST QUEATION)
mr Goodwill [35]

Answer:

Step-by-step explanation:

Weight decreased = 108 - 88 =  20 Kg

Percentage decrease = \frac{20}{108}*100

                   = 18.52%

3 0
3 years ago
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