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BartSMP [9]
2 years ago
5

If a=5 what is the value of the card 4a-2

Mathematics
2 answers:
mart [117]2 years ago
3 0

Answer:

18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

4a - 2

a = 5

<u>Step 2: Evaluate</u>

  1. Substitute in <em>a</em>:                   4(5) - 2
  2. Multiply:                              20 - 2
  3. Subtract:                             18
DaniilM [7]2 years ago
3 0

Answer:

The card "4a-2" is equal to 18

4a-2 = 18

Step-by-step explanation:

#1. Replace <em>a</em> with 5 and Your equation should look like the following:

4(5)-2

#2. Now Simplify, we all know that multiplication goes before subtraction or addition:

20-2

#3. Celebrate:

18

Woohoo

Hope this helps!

Have a nice day!

If you find my answer helpful

<em>Pls consider marking my answer as </em><em>Brainliest</em><em>! It would mean a lot!</em>

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Answer:

The 95%  confidence interval is

           0.45 <  \mu_1 - \mu_2  < 5.35

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1   =  36

   The first  sample mean is  \= x_1  =  3.5

   The first standard deviation is  \sigma_1  =  5.9 \ pounds

   The second  sample size is n_2 =  36

    The second  sample mean is  \= x_2 =  0.6

    The second  standard deviation is \sigma  =  4.4

Generally the degree of freedom is mathematically represented as

     df =  \frac{ [ \frac{s_1^2 }{n_1 }  + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2  }

=>  df =  \frac{ [ \frac{5.9^2 }{34 }  + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2  }

=>  df =63

Generally the standard error is mathematically represented as

      SE =  \sqrt{ \frac{s_1 ^2 }{n_1}  + \frac{s_2^2 }{ n_2 } }

=>  SE =  \sqrt{ \frac{ 5.9 ^2 }{ 36 }  + \frac{ 4.4^2 }{36} }

=>  SE = 1.227

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

     t_{\frac{\alpha }{2}, 63  } =  1.998

Generally the margin of error is mathematically represented as

        E =  t_{\frac{\alpha }{2}, 63  } *  SE

=>    E =  1.998 * 1.227

=>    E =  2.45

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 - \x_2) -E <  \mu

 => (3.5  - 0.6) - 2.45 <  \mu_1 - \mu_2  < (  3.5  - 0.6)  + 2.45

=>   0.45 <  \mu_1 - \mu_2  < 5.35

     

8 0
2 years ago
I need help please help me
Viktor [21]
(Scroll to the bottom to see my answer) The order of operations is PEMDAS aka Parentheses. Exponents. Multiplication or Division (Which ever come first). Addition or Subtraction (again whichever comes first). Start with (12-9)=3 then multiply 3 by 3, three times=9 then multiply 2 and 7 together=14 then do 9-14=-5

So my final answer is -5! I might be wrong but I did my best! I hope I’m not too late!
4 0
3 years ago
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