The value of the given surface integral is 4.
The given plane intercepts the coordinate axes at (2, 0, 0), (0, 2, 0), and (4, 0, 0). These point are the coordinates of a triangular region that we can parameterize using.
<h3>What is the surface integral?</h3>
A surface integral is a generalization of multiple integrals to integration over surfaces. It can be thought of as the double integral analog of the line integral. Given a surface, one may integrate a scalar field over the surface or a vector field.
with 0≤u≤1 and 0≤v≤1. Then the surface element ds is equivalent to
The surface integral is then
Therefore the value of the given surface integral is 4.
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Slope intercept form is y = mx + b
Pick one of the coordinates, I’ll use (-3,-4) as the example.
Coordinates are just numbers plugged in for (x,y).
This means -3 would be your x and -4 would be your y.
So plug these numbers into the equation and you get -4 = m(-3) + b.
M is slope and to find slope, you need to do (y2-y1) / (x2-x1).
In other words, it would be (-3 - -4) / (4 - -3) = 1/7 which is your slope (m).
Now plug that in for m to get the b variable.
-4 = 1/7(-3) + b.
B = -3.57
Your answer is y = 1/7x -3.57
120+.5x=50+.7x
Subtract 50 from both sides and then subtract .5x from both sides to get 70=.2x. Then divide both sides by .2 to get x=350.
0.4
4×1/10=0.4
multiply 4 by one-tenth
