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Gnom [1K]
3 years ago
6

A doctor studies the known cancer patients in a certain town. The probability that a randomly chosen resident has cancer is foun

d to be 0.0019. It is found that 28% of the town works for Ajax Chemical Company. The probability that an employee of Ajax has cancer is equal to 0.0019. Are the events "has cancer" and "works for Ajax" independent of one another?
Yes or No
Mathematics
1 answer:
Alex777 [14]3 years ago
4 0
Let the event 'has cancer' be C, and the event 'works for Ajax' be A.
P(C) = 0.0019. P(A) = 0.28
The events A and C are independent if P(C|A) = P(C).
P(C|A) = 0.0019 = P(C).
Therefore the answer is YES.

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Find x and the measure of each side. Round to two decimal places, if necessary.
natta225 [31]

The values of the triangles are as follows:

  • x = 7 units
  • GH = 21 units
  • HI = 21 units
  • GI = 12 units

<h3>How to find angles and side of a triangle?</h3>

The triangle is an isosceles triangle because two sides and angles are equal. Therefore,

4x - 7 = 2x + 7

4x - 2x = 7 + 7

2x = 14

x = 14 / 2

x = 7 units

GH = 4(7) - 7 = 28 - 7 = 21

HI = 2(7) + 7 = 14 + 7 = 21

GI = 7 + 5 = 12

learn more on triangle here: brainly.com/question/21279088

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3 0
2 years ago
If p = the price of a pair of basketball shoes, which algebraic expression
Kryger [21]
The answer will be D
7 0
3 years ago
Read 2 more answers
Consider function f and function g.
ivolga24 [154]

The statement the graphs of both functions have a vertical asymptote of x=0 and statement unlike the graph of function f, the graph of function g decreases as x increases are true.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have two functions:

f(x) = lnx

g(x) = -5 lnx

The domain of the both functions x > 0

The function will be touch the y-axis when x reaches to the infinite.

The graphs of both functions have a vertical asymptote of x=0.

Unlike the graph of function f, the graph of function g decreases as x increases.

The graph of function g is the graph of function f vertically stretched by a factor of 5 and reflected over the x-axis.

Thus, the statement the graphs of both functions have a vertical asymptote of x=0 and statement unlike the graph of function f, the graph of function g decreases as x increases are true.

Learn more about the function here:

brainly.com/question/5245372

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3 0
2 years ago
James is running late to his cousin's wedding and drives the 45 miles between his house and the wedding location 20 miles per ho
netineya [11]

Answer:

(r + 20)t = r

Step-by-step explanation:

Distance is constant in the scenario above, distance from home to wedding and wedding back home is the same.

From wedding back home. :

Recall : Distance = speed * time

Distance = r * 1 hour

From home to wedding :

Speed = 20 mph more ; r + 20

Time = t

Distance = (r + 20)* t = (r +20)t

Since the distance are the same, we can equate both :

(r + 20)t = r * 1

= (r + 20)t = r

5 0
3 years ago
A computer can be classified as either cutting dash edge or ancient. Suppose that 94​% of computers are classified as ancient. ​
taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94​% of computers are classified as ancient.

(a) <u>Two computers are chosen at random.</u>

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 2 computers

            r = number of success = both 2

           p = probability of success which in our question is % of computers

                  that are classified as ancient, i.e; 0.94

<em>LET X = Number of computers that are classified as ancient​</em>

So, it means X ~ Binom(n=2, p=0.94)

Now, Probability that both computers are ancient is given by = P(X = 2)

       P(X = 2)  = \binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}

                      = 1 \times 0.94^{2} \times 1

                      = 0.8836

(b) <u>Eight computers are chosen at random.</u>

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 8 computers

            r = number of success = all 8

           p = probability of success which in our question is % of computers

                  that are classified as ancient, i.e; 0.94

<em>LET X = Number of computers that are classified as ancient</em>

So, it means X ~ Binom(n=8, p=0.94)

Now, Probability that all eight computers are ancient is given by = P(X = 8)

       P(X = 8)  = \binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}

                      = 1 \times 0.94^{8} \times 1

                      = 0.6096

(c) <u>Here, also 8 computers are chosen at random.</u>

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 8 computers

            r = number of success = at least one

           p = probability of success which is now the % of computers

                  that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

<em>LET X = Number of computers classified as cutting dash edge</em>

So, it means X ~ Binom(n=8, p=0.06)

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X \geq 1)

       P(X \geq 1)  = 1 - P(X = 0)

                      =  1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}

                      = 1 - [1 \times 1 \times 0.94^{8}]

                      = 1 - 0.94^{8} = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge​ is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0
3 years ago
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