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nataly862011 [7]
3 years ago
13

What is an internal resistance?

Physics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

Internal resistance refers to the opposition to the flow of current offered by the cells and batteries themselves resulting in the generation of heat. Internal resistance is measured in Ohms. ... Example: 1 The potential difference across the cell when no current flows through the circuit is 3 V.

Thank you hope it is helpful to you if it is helpful then plz mark me as the brainlist

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insens350 [35]

Answer:

-\frac{1}{2}

Diverging lens

Explanation:

Given parameters:

Power of lens  = -2.0D

Unknown:

Focal length  = ?

Solution:

The power of lens is the reciprocal of the focal length;

   P  = \frac{1}{f}

where  f is the focal length

 f  = \frac{1}{P}   = -\frac{1}{2}

The lens is a diverging lens

8 0
2 years ago
If your bedroom is cold, you might feel warmer with several thin blankets than with one thick one
Nimfa-mama [501]

Answer: Yos

Explanation: Becouse i experimented that btw

4 0
3 years ago
What is the relationship between force and motion described by Newton's first law
prisoha [69]
Newtons First Law of Motion:
An object at rest stays at rest and an object in motion<span> stays in </span>motion <span>with the same speed and in the same direction unless acted upon by an unbalanced force.</span>

Therefore, the relationship between force and motion is that it takes force to change the speed or direction of any object in motion.
4 0
3 years ago
How is energy transferred between two objects at different temperatures?
mojhsa [17]

When calculated energy transferred between objects use the definition of heat as

4 0
3 years ago
An object is thrown directly downward from the top of a very tall building. The speed of the object just as it is released is 17
Softa [21]

Answer:

distance cover is  = 102.53 m

Explanation:

Given data:

speed of object is 17.1 m/s

t_1 = 3.32 sec

t_2 = 5.08 sec

from equation of motion we know that

d_1 = vt_1 + \frac{1}{2} gt_1^2

where d_1 is distance covered in time t1

sod_1 = 17.1 \times 3.32 + \frac{1}{2} 9.8 \times 3.32^2=

d_1 = 110.78 m

d_2 = vt_2 + \frac{1}{2} gt_2^2

where d_2 is distance covered in time t2

d_2 = 17.1 \times 5.08 + \frac{1}{2}\times9.8 \times 5.08^2

d_2 = 213.31 m

distance cover is  = 213.31 - 110.78 = 102.53 m

3 0
3 years ago
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