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Dima020 [189]
3 years ago
12

PLZ HURRY GOTTA HAVE IT DONE BEFORE MY MOM GETS HOME SHES 5 MINS AWAY!!!!!!!

Physics
1 answer:
Pie3 years ago
3 0

Answer:

The answer is B the products of photosynthesis are the reactants of cellular respiration

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How to find the density of air?
nikitadnepr [17]
You have to divide the pressure exerted by the air into two partial pressures: of the dry air and of the water vapor. Combining these two values gives you the parameter.
8 0
3 years ago
Motor oil , with a viscosity of 0 . 250 Ns / m2 , is flowing through a tube that has a radius of 5 . 00 mm and is 25 . 0 cm long
Thepotemich [5.8K]

Answer:

1.1775 x 10^-3 m^3 /s

Explanation:

viscosity, η = 0.250 Ns/m^2

radius, r = 5 mm = 5 x 10^-3 m

length, l = 25 cm = 0.25 m

Pressure, P = 300 kPa = 300000 Pa

According to the Poisuellie's formula

Volume flow per unit time is

V=\frac{\pi \times Pr^{4}}{8\eta l}

V=\frac{3.14 \times 300000\times \left ( 5\times 10^{-3} \right )^{4}}{8\times 0.250\times 0.25}

V = 1.1775 x 10^-3 m^3 /s

Thus, the volume of oil flowing per second is 1.1775 x 10^-3 m^3 /s.

3 0
3 years ago
A light source radiates 60.0 W of single-wavelength sinusoidal light uniformly in all directions. What is the amplitude of the m
Anna35 [415]

To solve this problem it is necessary to take into account the concepts of Intensity as a function of Power and the definition of magnetic field.

The intensity depending on the power is defined as

I = \frac{P}{4\pi r^2},

Where

P = Power

r = Radius

Replacing the values that we have,

I = \frac{60}{(4*\pi (0.7)^2)}

I = 9.75 Watt/m^2

The definition of intensity tells us that,

I = \frac{1}{2}\frac{B_o^2 c}{\mu}

Where,

B_0 =Magnetic field

\mu = Permeability constant

c = Speed velocity

Then replacing with our values we have,

9.75 = \frac{Bo^2 (3*10^8)}{(4\pi*10^{-7})}

Re-arrange to find the magnetic Field B_0

B_o = 2.86*10^{-7} T

Therefore the amplitude of the magnetic field of this light is B_o = 2.86*10^{-7} T

6 0
3 years ago
Which of these is the most likely impact of solar prominence on Earth?
svlad2 [7]

<span>Solar prominences themselves are of no concern because they are visible in the Hydrogen Alpha wavelength. They are anchored in place by magnetic fields. When these fields break or reconnect, it can send the plasma that makes up the prominence away from the sun. If one of these clouds impacts Earth, they are called CMEs or coronal mass ejections. Depending on the magnetic orientation of the cloud with respect to Earth's the CME can break down our magnetic field resulting in geomagnetic storms, aurorae, power grid fluctuations, and particle radiation near the poles, satellite single upset events, and radio blackouts. </span>

<span>
</span>

<span>Thus, letter a is the answer. </span>

8 0
3 years ago
If you were to compare three stars with the same surface temperature, with one star being a giant, another a supergiant, and the
Fudgin [204]

Answer:

Radii of Super giant > giant > main sequence star.

Explanation:

A star becomes a giant after all the hydrogen available for fusion, in a main sequence star is depleted and its outer shell of the star expands.

Super giant and giant stars are very large in size compared to a main sequence star. For example, if a giant star has 20 times the diameter of main sequence star, the super giant's diameter is almost 300 times or even more than a main sequence star.  

Most of the stars are main sequence stars. After a star has spent a few million or even a few billion years as a main sequence star, it becomes a giant and a super giant star. These are the later stages of development of development of the main sequence star. Giant and super giant phase of a star's life is very short compared to the main sequence star.

6 0
3 years ago
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