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3 years ago

What is the value of y in the solution to the following system of equations?

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

Answer:

Option D is the correct answer.

Step-by-step explanation:

The equations are:

5x - 3y = -11 Eqn 1

2x - 6y = -14 Eqn 2

We have to find the value of y so we will eliminate x.

Multiplying Eqn 1 by 2

2(5x-3y=-11)

10x-6y=-22 Eqn 3

Multiplying Eqn 2 by 5

5(2x-6y=-14)

10x-30y=-70 Eqn 4

Subtracting Eqn 4 from Eqn 3

(10x-6y)-(10x-30y)= -22-(-70)

10x-6y-10x+30y = -22 + 70

24y = 48

$\frac{24y}{24}=\frac{48}{24}\\y=2$

Therefore,

Option D is the correct answer.

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In her metalwork class, Anja cut a square of

Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

$Area=a^2$

Where, a is the edge of the square.

Area of the smaller square is:

$A_1=(3.7)^2$

$A_1=13.69$

Area of the larger square is:

$A_2=(6.3)^2$

$A_2=39.69$

The area of the remaining tin is:

$A=A_2-A_1$

$A=39.69-13.69$

$A=26$

Therefore, the area of the remaining tin is 26 sq. cm.

8 0

2 years ago

Find the missing angel

kolezko [41]

Answer:

x=25°

Step-by-step explanation:

The given angle is a 90° angle. We know this because of the little square in the corner. This means that both angles must add up to 90°:

$x+y=90$

Insert the known values:

$x+65=90$

Solve for x. Subtract 65 from both sides:

$x+65-65=90-65\\\\x=25$

The missing angle, x°, is 25°.

:Done

8 0

3 years ago

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Umnica [9.8K]

Answer:

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Step-by-step explanation:

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2 years ago

On a coordinate plane, a line is drawn from point C to point D. Point C is at (negative 1, 4) and point D is at (2, 0). Point C

skelet666 [1.2K]

Answer:

distance = 5 units

Step-by-step explanation:

In order to solve this problem we can start by plotting the two points you were provided with (see attached picture). This will help us visualize the problem better.

Now, we need to find the distance between those two points, so in order to do so we can use the distance formula:

$distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

in this case the x's and y's are given by the given points, since they are written as ordere pairs. And ordered pairs are written in the form (x,y). So for Point C:

C=(-1,4)

$x_{1}=-1$