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Elanso [62]
2 years ago
9

Multiply 8 by 10, then subtract t from the result

Mathematics
1 answer:
faltersainse [42]2 years ago
3 0

Answer:

80-t

Step-by-step explanation:

8(10)=80

80-t

Not sure if this is what you mean... please attach a picture to your question.

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In a rectangle the length is 6 more than twice the width, if the perimeter is 60 inches, what is the width of the rectangle
Vitek1552 [10]
Length(l)= 2w+6
width(w)= w

Perimeter(P)= 60 inches= 2w+2l (divide each side by 2 to simplify)
P=30 in= w+l

Plug in expression for "l" to be able to add like terms.
P=30=w+l
P=30=w+(2w+6)
P= 30= 3w+6
P= 24= 3w
w= 8 inches

Answer: 
The width of the rectangle is 8 inches.

7 0
3 years ago
Very important!! Solve the inequality 6r + 30 ≥ 12 or -r > 12 (the question is important for high school application c:)
Fofino [41]

First simplify the one inequality, 6r + 30 greater than or equal to 12 just divide by 6 then subtract 30 from both sides of the inequality. You should get r is greater than or equal to -3. For this one you need to reverse the inequality symbol then divide both sides by -1 to get a positive r, and you get r is less than -12. It's not A because there's two solutions, and it's not D for the same reason. It's not C because r isn't greater than -12. In conclusion it's B because it correctly represents the solutions that make the inequality true. I hope this helps you on your high school application :)

7 0
3 years ago
Beth is purchasing chocolate and vanilla ice cream cups for a birthday party. She needs a total of 24 ice cream cups and twice a
frez [133]
constraint 1
 let
 x = number of cups of chocolate
 y = number of cups of vanilla
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 x + y = 24
 constraint 2
 the ratio of the number of chocolate cups to vanilla cups is
 y = (1/2) x
 Using equations 1 and 2, you can find the number of cups of each favor required.
 answer:
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6 0
3 years ago
Simplify the expression (5-5i)-(-6-3i)
cupoosta [38]

Answer: Simplifying the expression of the substraction of the two complex numbers we get  11-2i


Solution:

(5-5i)-(-6-3i)

Eliminating the parentheses: 5-5i+6+3i

Grouping similar terms: (5+6)+(-5+3)i

Adding the similar terms: 11+(-2)i = 11-2i

7 0
3 years ago
Read 2 more answers
Dada la recta r espacio dos puntos espacio fracción numerador x menos 1 entre denominador 1 fin fracción igual fracción numerado
Kruka [31]

Answer:

creo que si

Step-by-step explanation:

primero hacemos lo primero

y luego lo segundo

5 0
3 years ago
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