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Inga [223]
3 years ago
15

Find the slopes between 9,3 and -2,2

Mathematics
2 answers:
velikii [3]3 years ago
6 0
Think this in mind first. The y-values first so.
And then subtract. The second y-value subtract with the first one.
2-3= -1
Then now the x-values.
-2-9=-11.
What do you have now ? It will be -1 and -11. Now you have to simplify and make it positive and it should be looking like this
-1/-11 —-> 1/11
blsea [12.9K]3 years ago
4 0

Answer:

1/11

Step-by-step explanation:

to find slope use y2-y1 / x2-x1

So here the 2 is the 2nd y point, and the 3 is the 1st y point, so the first part is

2-3

then the 2nd x point is -2, and the 1st x point is 9, so the second part is

-2-9

So together its

2-3 / -2-9

2-3 is -1, and -2-9 is -11, so it's

-1 / -11, which is basically just 1 / 11

So the slope is 1 / 11

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V = u + at<br><br> u = 2 a = -5 t = 1/2
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v = -0.5

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Section B
MA_775_DIABLO [31]

Answer/Step-by-step explanation:

Using α as reference angle:

Perpendicular side = BC (one of the legs that adjoins to form a right angle. It is opposite to the reference angle.)

Base side = AB (The other leg that forms a right angle with the perpendicular side at the adjoining point. It is adjacent to the reference angle)

Hypotenuse = AC (the side opposite to the right angle, 90°)

Using β as reference angle:

Perpendicular side = AB (one of the legs that adjoins to form a right angle. It is opposite to the reference angle.)

Base side = BD (The other leg that forms a right angle with the perpendicular side at the adjoining point. It is adjacent to the reference angle)

Hypotenuse = AD (the side opposite to the right angle, 90°)

5 0
4 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
jok3333 [9.3K]

The point-slope form:

y-y_1=m(x-x_1)

m - slope

We have the line

y-3=-\dfrac{1}{5}(x+2)\to m=-\dfrac{1}{5}

If m₁ and m₂ are the slopes of the perpendicular lines, then

m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

Therefore the slope of ouer line is

m=-\dfrac{1}{-\frac{1}{5}}=5

We have the point (-2, 7). Put the coordinates to the equation of a line in the point-slope form:

y-7=5(x-(-2))

y-7=5(x+2)      <em>use the distributive property</em>

y-7=(5)(x)+(5)(2)

y-7=5x+10       <em>add 7 to both sides</em>

\boxed{y=5x+17}

7 0
3 years ago
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