Let us assume the regular price of each tube of paint = r.
0.50 off each tube.
New price of each tube = r - 0.50.
She buy 6 tubes.
Total price of 6 tubes = 6×(r-0.50).
We are given total price = $84.30 .
Therefore, we can setup an equation
6×(r-0.50) = 84.30.
Distributing 6 over (r-0.50), we get
6r - 3.0 = 84.30
Adding 3.0 on both sides, we get
6r - 3.0+3.0 = 84.30+3.0
6r = 87.30
Dividing both sides by 6, we get
6r/6 = 87.30/6
r = 14.55
<h3>Therefore, required equation is
6(r-0.50) = 84.30 and the regular price of each tube of paint is $14.55.</h3>
3:9 You may be asking "THAT'S IT?" but yeah thats all you have to do. Not for all problems thought
Answer:
EF = 19
Step-by-step explanation:
EF = (23 + 15)/2 = 19
Answer:
the area of the curve y= f(x) = x between x = 5 and x = 10
Step-by-step explanation:
- Finding the area of the curve y = f(x) = x between x = 5 and x = 10
Using the Area formula
As the area of curve lies between x = 5 and x = 10
so
so the integral expression becomes
![A=\left[\frac{x^{1+1}}{1+1}\right]^{10}_5](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cfrac%7Bx%5E%7B1%2B1%7D%7D%7B1%2B1%7D%5Cright%5D%5E%7B10%7D_5)
![=\left[\frac{x^2}{2}\right]^{10}_5](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cright%5D%5E%7B10%7D_5)
![=\frac{1}{2}\left[10^2-5^2\right]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Cleft%5B10%5E2-5%5E2%5Cright%5D)
Therefore, area of the curve y= f(x) = x between x = 5 and x = 10
