Answer:
Option C: 0.28
Step-by-step explanation:
This is a binomial probability distribution problem.
Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;
P(X ≥ 2) = P(2) + P(3) + P(4) + P(5)
From the histogram;
P(5) = 0.02
P(4) = 0.02
P(3) = 0.05
P(2) = 0.19
Thus;
P(X ≥ 2) = 0.19 + 0.05 + 0.02 + 0.02
P(X ≥ 2) = 0.28
<span>2x+3y=3
</span><span>-3x-2y=8
3y=3-2x
-2y = 8+3x
y = 1 - 2x/3
y = -4 - 3x/2
</span>1 - 2x/3 = -4 - 3x/2
5 = - 3x/2 + 2x/3
5 = -9x/6 + 4x/6
5 = -5x/6
x = 5 * 6/-5
x = -6
No plug it in.
<span>2x+3y=3 ; x = -6
-12 + 3y = 3
3y=3+12
3y=15
y = 5
So </span>x = -6 and y = 5