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3 years ago

Choose the properties that can be use to rewrite. brainliest for correct answer <3

Mathematics

2 answers:

kumpel [21]3 years ago

8 0

The answer is communicative property

algol [13]3 years ago

5 0

Answer:

I think the correct answer is the communitive property.

Step-by-step explanation:

please tell me if wrong.

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Calcule o saldo de salário, o funcionário foi admitido em 10 de janeiro como mensalista, salário R$ 1400,00?

Sholpan [36]

Responda:

$ 980

Explicação passo a passo:

Dado que:

Salário mensal = $ 1400

Data de emprego = 10 de janeiro

Usando o sistema de mês de 30 dias:

Taxa diária =. $ 1400/30 = $ 46.66666

Dias não trabalhados = janeiro - 9 de janeiro = 9 dias

Subtraia o salário de 9 dias do total:

Salário total - (9 * taxa diária)

$ 1400 - (9 * $ 46,66666)

$ 1400 - $ 420

= $ 980

Portanto, o saldo do salário é de $ 980

7 0

2 years ago

I really need help I don't know what to do I pay attention but don't understand

mrs_skeptik [129]

It means like what number equals that number.Use multiplication to figure these out.

Example : 9,15. Factors for 9-9,1,3 .Factors for 15-1,15,3,5

Hope this helps !

6 0

3 years ago

Will give 25 points and brainliest answer if correct

AleksAgata [21]

The first term a1 is given to be -4. The formula for the next terms: an = an-1 + 7 means to add 7 to the previous term to get the next.

-4, 3, 10, 17, 24, 31

Answer A

5 0

3 years ago

Read 2 more answers

SOMEONE HELP ME PLEASE

yawa3891 [41]

Answer:

x=8

Step-by-step explanation:

the y-value in the first pair decreased by half, so the x-value must double due to inverse variation.

8 0

3 years ago

Which expression should you simplify to find the 90% confidence interval,

Alex787 [66]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value is:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

8 0

2 years ago