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Rama09 [41]
3 years ago
13

Use the drop-down menus to identify the resulting expressions based on the given steps,

Mathematics
2 answers:
Svetlanka [38]3 years ago
6 0
The answer is going to be 97
Gre4nikov [31]3 years ago
4 0

Answer:

the answer is 97.

Step-by-step explanation:

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A train traveled 210 miles in 3.5 hours to its first stop. It then continued on traveling another 130 miles in 2.5 hours. What w
valkas [14]
T = 6 [h]
s = 340 [mi]

v=s/t=340/6=56.7 [mi/h]
Answer C.
8 0
3 years ago
Find the product of (2x-3) and (x+3)​
miss Akunina [59]

Answer:

(2x - 3) * (x + 3)

=> (2x * x) + (-3 * 3)

=> 2x - 9

=> 2x -9

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

3 0
3 years ago
HELP ME PLEASE ON THIS!!
Nata [24]

Answer:

On the ground is the answer and my chat is "devanson1".

Step-by-step explanation:

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6 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Give the discriminant of the equation 0 = −x2+6x−9<br>please answer
Brut [27]

Answer:

x = 3

Steps:

- ( {x}^{2}  - 6x + 9) = 0

-  {(x - 3)}^{2}  = 0

{(x - 3)}^{2}  = 0

x - 3 = 0

There you go!

8 0
3 years ago
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