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baherus [9]
3 years ago
14

1. Name an example of a real-world data set, not yet mentioned in the course, where you would typically expect to see a normal d

istribution. Be sure to describe what the labels would be for the horizontal and vertical axis of the display. Then explain why you would expect a normal distribution. What range of data values would you expect to represent 1 standard deviation from the mean? (15 points; 10 for your answer, 5 for response to others' comments.)​
Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

1.The heights of students in a class, for example, would have a normal distribution. We expect a few students to be extremely tall and a few to be extremely short, but the majority will be in the middle. On the x-axis, we'll have heights, and on the y-axis, we'll have the frequency of the number of students with heights. According to the empirical rule, 68 percent of the data could fall within one standard deviation of the mean.

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65% of what number is 39?
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You should get 60 as your final answer.
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The dimensions of a rectangular prism can be expressed as width w,length w+4, and height 5-w.What is the approximate width (w) t
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Given cos x=0.4762,find the degree measure of x.round your answer to the nearest tenth
alex41 [277]

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3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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