Its the first one because -3(-2)=6, 1(-2)=-2, 2(-2)=4 are all correct
1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
In 864 it is a tenth as large... Hope that helped lol i'm not completely sure. I did it in my head.
Answer:
False
Step-by-step explanation:
A line is defined by and consists of at least two points, therefore, an extra point in the same plane can be located such that when joined to one of the previous two points to form another distinct line
However, three points can only lie on one distinct plane as the location of the third point together with the two colinear point form either three colinear points or a triangle which is a planar two dimensional polygon.
Answer:
x = 71.5 in
Step-by-step explanation:
Remember the SOHCAHTOA rule
Soh...
Sine = Opposite / Hypotenuse
...cah...
Cosine = Adjacent / Hypotenuse
...toa
Tangent = Opposite / Adjacent
In this case, we use: CAH.
cos(52) = 44/x
x = 44/cos(52)
x = 71.5 inches