Answer:
- def getCharacterForward(char, key):
- charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
-
- if(len(char) > 1):
- return None
- elif(not isinstance(key, int)):
- return -1
- else:
- index = charList.find(char)
- if(index + key <= 25):
- return charList[index + key]
- else:
- return charList[(index + key)% 26]
-
- print(getCharacterForward("C", 4))
- print(getCharacterForward("X", 4))
Explanation:
Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.
Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).
Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).
However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).
We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:
G
B
Answer:
Following are the code block in the Java Programming Language.
//define recursive function
public static long exponentiation(long x, int n) {
//check the integer variable is equal to the 0.
if (x == 0) {
//then, return 1
return 1;
}
//Otherwise, set else
else {
//set long data type variable
long q = exponentiation(x, n/2);
q *= q;
//check if the remainder is 1
if (n % 2 == 1) {
q *= x;
}
//return the variable
return q;
}
}
Explanation:
<u>Following are the description of the code block</u>.
- Firstly, we define the long data type recursive function.
- Then, set the if conditional statement and return the value 1.
- Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
- Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.
Answer:
Development task is the correct answer to the given question.
Explanation:
The database administrator is responsible for managing the database management system . The overall security of the database is depended on the database administrator.
The Development task include the following function
- Verification of the data model that is used by the database management system .
- Check the user input it means validating the data.
- Defining the overall requirement to create the model.
- Providing backup when the data is loss .
So the Development task is the correct answer.
Answer: what are the choices?
Explanation:
Answer:
It for shadows the reason that peles temper is not just a rumor wich is proven in the answer she gives
Explanation:
it says that you should forget the rumors and her fiery temper whic means ti is true
