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alexandr1967 [171]
3 years ago
7

Select the correct answer. Which graph shows a function and its inverse?

Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer:

first graph shows the function and it's inverse

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Solve for a<br><br> a² + 7a - 8 = 0
masya89 [10]

Answer:

a=-8

Step-by-step explanation:

5 0
3 years ago
From the top of the Eiffel Tower, a jogger is spotted heading toward the tower. When at position A, the angle of depression of t
8090 [49]

325 meters if using full height of 324 meters for tower 
277 meters if using observation platform height of 276 meters.  
When the depression is 37 degrees, you can create a right triangle with the angles 90, 37, and 53 degrees. The distance from a point directly underneath the observer will be:
 h/tan(37)
 where
 h = height of the observer.
 
 And when the depression is 72 degrees, the distance will be:
 h/tan(72) 
 So the distance between the two points will be the absolute value of:
 h/tan(72) - h/tan(37)
 =(tan(37)h)/tan(37)tan(72) - tan(72)h/(tan(37)tan(72))
 =(tan(37)h - tan(72)h) /(tan(37)tan(72))
 =h(0.75355405 - 3.077683537)/(0.75355405 * 3.077683537)
 =h(0.75355405 - 3.077683537)/(0.75355405 * 3.077683537)
 =h(-2.324129487/2.319200894)
 =h*-1.002125125
 
 And since we're looking for absolute value
 =h*1.002125125
 
 As for the value of "h" to use, that's unspecified in the problem. If you take h
to be the height of the Eiffel Tower, then it's 324 meters. If you take h to be
the highest observation platform on the Eiffel Tower, then it's 276 meters. In
any case, simply multiply h by the value calculated above:
 =h*1.002125125
 =324*1.002125125
 = 324.6885406 m
 
 =h*1.002125125
 =276*1.002125125
 =276.5865346

6 0
3 years ago
What is the distance between -4.32 and 0 on the number line?
saveliy_v [14]

B looks the most reasonable

5 0
3 years ago
Read 2 more answers
Given the line below.
Elza [17]

The slope of that line is -1, so m = -1.

The point you were told to use is (-2,2), so point-slope form starts as:

   ( y - 2 ) = -1 • ( x - (-2) )

But we'd clean up that x-(-2) to be x+2.

   y - 2 = -1 ( x+2 )

7 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=74,000+80x
SOVA2 [1]

Answer:

a) $675000

b) $289000 profit,3300 set, $190 per set

c) 3225 set, $272687.5 profit, $192.5 per set

Step-by-step explanation:

a) Revenue R(x) = xp(x) = x(300 - x/30) = 300x - x²/30

The maximum revenue is at R'(x) =0

R'(x) = 300 - 2x/30 = 300 - x/15

But we need to compute R'(x) = 0:

300 - x/15 = 0

x/15 = 300

x = 4500

Also the second derivative of R(x) is given as:

R"(x) = -1/15 < 0 This means that the maximum revenue is at x = 4500. Hence:

R(4500) = 300 (4500) - (4500)²/30 = $675000  

B) Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 80x) = -x²/30 + 300x - 80x - 74000

P(x) = -x²/30 + 220x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 220= -x/15 + 220

But we need to compute P'(x) = 0:

-x/15 + 220 = 0

x/15 = 220

x = 3300

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3300. Hence:

P(3300) =  -(3300)²/30 + 220(3300) - 74000 = $289000  

The price for each set is:

p(3300) = 300 -3300/30 = $190 per set

c) The new cost is:

C(x) = 74000 + 80x + 5x = 74000 + 85x

Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 85x) = -x²/30 + 300x - 85x - 74000

P(x) = -x²/30 + 215x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 215= -x/15 + 215

But we need to compute P'(x) = 0:

-x/15 + 215 = 0

x/15 = 215

x = 3225

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3225. Hence:

P(3225) =  -(3225)²/30 + 215(3225) - 74000 = $272687.5

The money to be charge for each set is:

p(x) = 300 - 3225/30 = $192.5 per set

When taxed $5, the maximum profit is $272687.5

3 0
3 years ago
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