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solniwko [45]
3 years ago
11

Beverly made a root beer float using 1/4 cup of vanilla ice cream for every 3/4 cup of root beer. how much ice cream would Bever

ly need for one cup of root beer?
Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

1/3 cup of ice icream

Step-by-step explanation:

This is a proportions question. Since we know that we need 1/4 cup of ice cream for every 3/4 cup of root beer, we need to find how many cups of ice cream we need for 1 cup of root bear.

We need to find out what times 3/4 makes 1. This can be done with:

(3/4)x = 1

x = 4/3

Now multiply that with 1/4 to get the amount of ice cream.

4/3 times 1/4 = 1/3

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Answer:

\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095

-The sample is too small to make judgments about skewness or symmetry.

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013

p_v =2*P(t_{(14)}

So the p value is a very high value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

Step-by-step explanation:

First we need to find the difference defined as:

(Operator 1 minus Operator 2)

d1=1.326-1.323=0.003      d2=1.337-1.322=0.015

d3=1.079-1.073=0.006     d4=1.229-1.233=-0.004

d5=0.936-0.934=0.002   d6=1.009-1.019=-0.01

d7=1.179-1.184=-0.005      d8=1.289-1.304=-0.015

Now we can calculate the mean of differences given by:

\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001

And for the sample deviation we can use the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095

Describe the distribution of these differences using words. (which one is correct)

We can plot the distribution of the differences with the folowing code in R

differences<-c(0.003,0.015,0.006,-0.004,0.002,-0.01,-0.005,-0.015)

hist(differences)

And we got the image attached. And we can see that the distribution is right skewed but we don't have anough info to provide a conclusion with just 8 differnences.

-The sample is too small to make judgments about skewness or symmetry.

Use a significance test to examine the null hypothesis that the two operators have the same mean. Give the test statistic. (Round your answer to three decimal places.)

\bar X_{1}=1.173 represent the mean for the operator 1

\bar X_{2}=1.174 represent the mean for the operator 2

s_{1}=0.1506 represent the sample standard deviation for the operator 1

s_{2}=0.1495 represent the sample standard deviation for the operator 2

n_{1}=8 sample size for the operator 1

n_{2}=8 sample size for the operator 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) like this:

t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=8+8-2=14

Since is a bilateral test the p value would be:

p_v =2*P(t_{(14)}

So the p value is a very high value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

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lora16 [44]

Answer

~~~~~~~~~~~~

slope: 1

y intercept: 4

equation: y=x+4

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Alenkasestr [34]

Answer:

Domain: {-4, -2, 1, 2, 4}

Range: {-4, -2, -1, 1, 4}

The relation is a function.

Step-by-step explanation:

A <u>relation</u> is any set of ordered pairs, which can be thought of as (input, output).

A function is a <em>relation</em> in which no two ordered pairs have the same first component and different second components.

Remember that a function can only take on <u>one output for each input</u>. We cannot plug in a value and get out two values.

The Vertical Line Test allows us to know whether or not a graph is actually a function.  If a vertical line intersects the graph in all places <u><em>at exactly one point</em></u>, then the relation is a function.

I did the Vertical Line Test on your given graph. As you can see from the attached screenshot, each vertical line crosses the graph only once. Therefore, the given relation is a function.

The <u><em>domain</em></u> of the given relation is the set of x-values, while the <em><u>range</u></em> is the set of y-values. You'll have to list the ordered pairs in order to determine the domain and range of the given relation.

Relation:  {(-4, -1), (-2, 1), (1, -2), (2, 4), (4, -4)}.

Domain: {-4, -2, 1, 2, 4}

Range: {-4, -2, -1, 1, 4}

Please mark my answers as the Brainliest if you find my explanations helpful :)

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3 years ago
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