Answer:
To construct the Square using a compass and straight edge, you have written the steps not in proper order. I am rearranging the steps for you
1. Construct horizontal H J¯¯¯¯¯
2. Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .
3.Label the point of intersection of the two circles above HJ¯¯¯¯¯ , point K, and the point of intersection of the two circles below HJ¯¯¯¯¯ , point L.
4.Construct KL¯¯¯¯¯ , the perpendicular bisector of HJ¯¯¯¯¯ , intersecting HJ¯¯¯¯¯ at point M.
5.Construct a circle with point M as the center with radius MJ .
6.Label the point of intersection of circle M and KL¯¯¯¯¯ closest to point K, point N, and the point of intersection of circle M and KL¯¯¯¯¯ closest to point L, point O.
7.Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .
Answer:
a) linear pair angles: 1&2, 2&3, 3&4, 1&4... etc (any angles that are adjacent, or right next, to each other that add up to be 180 degrees)
b) All linear pair angles are adjacent angles but not all adjacent angles are linear pairs. So pick any linear pair angle you got because they will always be adjacent. (1&2, 2&3, 3&4, 1&4... etc)
c) vertically opposite angles: 1&3, 2&4, 5&7, 6&8, 9&11, 10&12
Step-by-step explanation:
Answer:
(e) csc x − cot x − ln(1 + cos x) + C
(c) 0
Step-by-step explanation:
(e) ∫ (1 + sin x) / (1 + cos x) dx
Split the integral.
∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx
Multiply top and bottom of first integral by the conjugate, 1 − cos x.
∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx
Pythagorean identity.
∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx
Divide.
∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx
Integrate.
csc x − cot x − ln(1 + cos x) + C
(c) ∫₋₇⁷ erf(x) dx
= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx
The error function is odd (erf(-x) = -erf(x)), so:
= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx
= 0
Solution: The commutative property of addition states that when two numbers are being added, their order can be changed without affecting the sum.
10.05 = 10 5/100 = 10 1/20
10.005 = 10 5/1000 = 10 1/200
therefore, 10.05 is greater then 10.005
