All categories

3 years ago

Find the area of the shape shown below.

Mathematics

1 answer:

Sveta_85 [38]3 years ago

4 0

Answer:

<em>32 units² </em>

Step-by-step explanation:

$A_{1}$ = 4(2 + 2 + 6) ÷ 2 = 20

$A_{2}$ = (2 × 2) ÷ 2 = 2

$A_{3}$ = 2² = 4

$A_{4}$ = 2 × 6 ÷ 2 = 6

A = $A_{1}$ + $A_{2}$ + $A_{3}$ + $A_{4}$ = <em>32 units²</em>

You might be interested in

Xto the 2nd power - 49 = 0

AnnZ [28]

Answer:

7 to the second power... because 7 times is 49 and 49-49 is 0... so 7 to the second power

6 0

3 years ago

Easy 6th grade math

Grace [21]

Answer:

18 in

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Only the smartest person in their math class can help me with this difficult problem!!!

vodomira [7]

Step-by-step explanation:

$\tt{(5 {x}^{3} - 3x + 6) - (2 {x}^{2} - 4x + 8)}$

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ $\tt{5 {x}^{3} - 3x + 6 - 2 {x}^{2} + 4x - 8}$

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶ $\tt{5 {x}^{3} - 3x + 4x + 6 - 8 - 2 {x}}^{2}$

⟶ $\tt{5 {x}^{3} + x - 2 - 2 {x}^{2} }$

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

$\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \tt{5 {x}^{3} - 2 {x}^{2} + x - 2}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

6 0

2 years ago

Read 2 more answers

Which represents r in terms of A and S?

ladessa [460]

Answer:

$r=\frac{6\sqrt{10AS}}{S\sqrt{\pi }}$

Step-by-step explanation:

Given the formula;

$A=\frac{\pi r^2S}{360}$

We want to solve the given formula for r.

Multiply both sides by $\frac{360}{\pi S}$

$A\times \frac{360}{\pi S}=\frac{\pi r^2S}{360} \times \frac{360}{\pi S}$

$A\times \frac{360}{\pi S}=r^2$

Take square root of both sides

$r=\sqrt{\frac{360A}{\pi S}}$

$r=\frac{\sqrt{360A}}{\sqrt{\pi S}}$

$r=\frac{\sqrt{360A}}{\sqrt{\pi }\sqrt{S}}$

$r=\frac{\sqrt{360A}\times \sqrt{S}}{\sqrt{\pi }\sqrt{S} \times \sqrt{S}}$

$r=\frac{\sqrt{360AS}}{S\sqrt{\pi }}$

$r=\frac{6\sqrt{10AS}}{S\sqrt{\pi }}$

5 0

3 years ago

....................................e..................................

lina2011 [118]

Answer:

what?

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers