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3 years ago

Find the area of the shape shown below.

Mathematics

1 answer:

Sveta_85 [38]3 years ago

4 0

Answer:

32 units²

Step-by-step explanation:

$A_{1}$ = 4(2 + 2 + 6) ÷ 2 = 20

$A_{2}$ = (2 × 2) ÷ 2 = 2

$A_{3}$ = 2² = 4

$A_{4}$ = 2 × 6 ÷ 2 = 6

A = $A_{1}$ + $A_{2}$ + $A_{3}$ + $A_{4}$ = 32 units²

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olga2289 [7]

Step $1$

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Let

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Step $2$

Find the slope of the line that is perpendicular to the given line

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to $-1$

$mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}$

Step $3$

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we know that

the equation of the line in the form point-slope is equal to

$y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5$

Multiply by $3$ both sides

$3y=5x-15$

$5x-3y=15$

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation $5x-3y=15$

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