Circumference=2πr=2×22/7×4.7=29.5 inch (nearly)
Answer:
that is not a function because for one value of x you get two different values of y. it is circle (x+3)^2+(y-3)^2=9. but if you divide it in two half circles (upper and lower) than you have two functions y=3+sqrt(-x^2-6x) and y=3-sqrt(-x^2-6x)
domain is x ∈ [-6,0] and range y ∈ [0,3] for one and for other y ∈ [3,6]
Answer:
no real solutions
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 : a ≠ 0
Then the nature of the roots can be determined from the discriminant
b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then no real roots
Given
n(7n + 8) = - 10 ← distribute left side
7n² + 8n = - 10 ( add 10 to both sides )
7n² + 8n + 10 = 0 ← in standard form
with a = 7, b = 8 and c = 10, thus
b² - 4ac = 8² - (4 × 7 × 10) = 64 - 280 = - 216
Since b² - 4ac < 0 the equation has no real roots
Answer:
x² + 10x - 24
Step-by-step explanation:
Given the roots are x = - 12 and x = 2 then the corresponding factors are
(x + 12) and (x - 2) and their product equals zero , that is
(x + 12)(x - 2) = 0 ← expand using FOIL
X² + 10X - 24 = 0