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matrenka [14]
3 years ago
5

Please help!!!!!! Explain the answer

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Answer:

I think they are.

Step-by-step explanation:

Because they are both 39 and 34 degrees so if x and y are the same number they are similar.

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Using the data set provided below, order the values from greatest to least.
lianna [129]
The answer will be E
6 0
3 years ago
What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30​
tia_tia [17]

Answer:

16

Step-by-step explanation:

ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30

number of terms =13

median=[(n+1)/2] th term

=[(13+1)/2] th term

=[14/2] th tem

=7th term

=16

7 0
3 years ago
If 5x - 3y = 1 and x = 2y - 4, then x • y = ?
Inessa05 [86]

Answer:

x = 2,  y = 3

Step-by-step explanation:

i) It is given that 5x - 3y =1

ii) It is also given that x = 2y - 4

iii) we can substitute the value of x from ii) in the equation in i) and we will get 5(2y - 4) - 3y = 1   ⇒ 10y - 20 -3y =  1   ⇒  7y = 21  ∴ y = 3

iv) substituting the value of y obtained in ii) we get x = (2 × 3) - 4 = 6 - 4 = 2.

v) Therefore x = 2.

4 0
3 years ago
Graph the function.<br><br> y = 1/5 (3)^x<br><br> Graph A. B. C. or D?
patriot [66]

The function y=3^x is incresing and have positive values for all x. Then the function y=\dfrac{1}{5}\cdot 3^x is also increasing and have positive values for all x. This means that options B (values are negative) and D (function is decreasing) are incorrect.

At x=0, y=\dfrac{1}{5} \cdot 3^x=\dfrac{1}{5} \cdot 3^0=\dfrac{1}{5} \cdot 1=\dfrac{1}{5}.

In option A graph of the function passes through point (0,y), where y is near 3. In option C graph of the function passes through point (0,y), where y is near 1/5. So, you can conclude that the option C is correct.

8 0
3 years ago
Find all points on the x-axis that are 14 units from the point (4, -7).
BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

Distance between two points:

Suppose we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

\sqrt{(x-4)^2+(0-(-7))^2} = 14

\sqrt{x^2 - 8x + 16 + 49} = 14

\sqrt{x^2 - 8x + 65} = 14

(\sqrt{x^2 - 8x + 65})^2 = 14^2

x^2 - 8x + 65 - 196 = 0

x^2 - 8x - 131 = 0

So a = 1, b = -8, c = -131

\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588

x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12

x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12

The points are: (16.12,0),(-8.12,0).

4 0
3 years ago
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