2 years ago

XY = 3cm, XŻY = 30° and YZ = x, Is itpossible to solve for x using the theorem of Pythagoras?

Mathematics

1 answer:

statuscvo [17]2 years ago

8 0

If you help me I would help you to

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2 years ago

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .

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XY = 3cm, XŻY = 30° and YZ = x, Is itpossible to solve for x using the theorem of Pythagoras? ​

XY = 3cm, XŻY = 30° and YZ = x, Is itpossible to solve for x using the theorem of Pythagoras?