we know that
A half-acre is equal to----------> 
Let
x---------> the length side of the building lot
y--------> the width side of the building lot
A------> Area of the building lot
x=5y-------> equation 1


--------> equation 2
substitute equation 1 in equation 2
![2,023.43=[5y]*y](https://tex.z-dn.net/?f=2%2C023.43%3D%5B5y%5D%2Ay)

<u>Find the value of x</u>

therefore
<u>the answer is</u>
the dimensions of the building lot are 100.55 m* 20.11 m
Answer:
the yo u thichi cutis lo u you
If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
13) B. 8.47,8.67,8.7
14) A
Just ask for explanation if u need it
Hope that helped :)