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Sladkaya [172]
3 years ago
7

Do all number lines show only whole number

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

no

Step-by-step explanation:

no because some numbers could be negative and most number lines also contain 0. whole numbers are positive, non decimal/fractional, real numbers

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Determine the value of the expression: 5^4 × 5^8/5^6 Write your answer in exponential notation (in exponent form).
4vir4ik [10]

Answer:

5⁶

Step-by-step explanation:

We have

5^4*\frac{5^8}{5^6}\\\frac{x^n}{x^y}=x^{n-y}\\\frac{5^8}{5^6}=5^{8-6}=5^2\\x^n*x^y=x^{n+y}\\5^4*5^2=5^6

6 0
3 years ago
A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be use
Aleks [24]
The answer to your question is: .75 = 3x - .03

How to solve it:

x = the cost of a pack of gum twenty years ago

.75 =  3x - .03
+ .03      + .03

.78 = 3x
 / 3    / 3         

.26 = x

If a pack of gum now costs 75 cents, which is 3 cents less than three times what a pack would have cost 20 years ago, then a pack of gum would have cost 26 cents. 
6 0
3 years ago
Read 2 more answers
Since a light year is a unit of astronomical distance equal to the distance light travels in one year, which phrase best complet
soldi70 [24.7K]

Answer:

B

Step-by-step explanation:

light takes around 3-5 mins from the sun to reach earth

8 0
3 years ago
Read 2 more answers
The Bobcats football coach logged the following yardage gains and losses over four plays of a game.
lions [1.4K]
Answer:
9.8x - 11.1x
Explanation:
25 - 5.2 = 9.8x
0.9 - 12 = -11,1y

Notice: I’m not sure but if it wrong, you could replaced with 10x - 11y which be better answer
5 0
3 years ago
For a process, the average range for all samples was 5 and the process average was 25. If the sample size was 10, calculate UCL
alexira [117]

Answer:

8.885

Step-by-step explanation:

Given that :

Sample size, n = 10

The average range, Rbar for all samples = 5

The upper control limit, UCL for the R-chart is :

UCL L= D4Rbar

From the control chart constant table, D4 = 1.777

Hence,

UCL = 1.777 * 5

UCL = 8.885

The UCL for the R-chart is 8.885

7 0
3 years ago
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