Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
Answer: x= -6 x=6
Step-by-step explanation:
expand the equation so you get (x-6)(x+6) and then set the equal to zero and solve
The y intercept of the graphed function and the equation are both -2
(I'm not entirely sure what the question is asking as some of it is blocked out from the drop down box?)
For the sequence 2, 6, 18, 54, ..., the explicit formula is: an = a1 ! rn"1 = 2 ! 3n"1 , and the recursive formula is: a1 = 2, an+1 = an ! 3 . In each case, successively replacing n by 1, 2, 3, ... will yield the terms of the sequence. See the examples below.
Answer:
8.7
Step-by-step explanation:
Since a square has equal side lengths, the formula for area is s^2, where s stands for side. Since we are given the area, s^2=75 square feet. Take the square root of both sides to get s is equivalent to the square root of 75 square feet. When this becomes a decimal, it is 8.66 feet. Since we are supposed to round to the nearest tenths, it rounds up to 8.7 feet per side length
