We can do like we did before, distribute the denominator,
Which postulate can be used to prove that the triangles are congruent?
1 answer:
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Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.