Answer: 28
Step-by-step explanation:
Given
Kenny made 7 serves over the net for every 2 serves that did not go over the net i.e. success rate of Kenny is
![\Rightarrow \text{success rate}=\dfrac{7}{2+7}\times 100=\dfrac{700}{9}\%](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctext%7Bsuccess%20rate%7D%3D%5Cdfrac%7B7%7D%7B2%2B7%7D%5Ctimes%20100%3D%5Cdfrac%7B700%7D%7B9%7D%5C%25)
for 36 serves, applying the same success rate, it is
![\Rightarrow \text{success rate}=\dfrac{700}{9}\times\dfrac{1}{100}\times 36=28](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctext%7Bsuccess%20rate%7D%3D%5Cdfrac%7B700%7D%7B9%7D%5Ctimes%5Cdfrac%7B1%7D%7B100%7D%5Ctimes%2036%3D28)
Serves that did not make over the net is ![36-28=8](https://tex.z-dn.net/?f=36-28%3D8)
Thus, Kenny will make 28 serves that make over the net
-9.4=>1.7x+4.2
-1.7x=>13.6
x<=8
Answer:
4.6%.
Step-by-step explanation:
The probability that a can of paint contains contamination(C) is 3.23%
P(C)=3.23%
The probability of a mixing(M) error is 2.4%.
P(M)=2.4%
The probability of both is 1.03%.
![P(C \cap M)=1.03\%](https://tex.z-dn.net/?f=P%28C%20%5Ccap%20M%29%3D1.03%5C%25)
We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. ![P(C \cup M)](https://tex.z-dn.net/?f=P%28C%20%5Ccup%20M%29)
In probability theory:
![P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%](https://tex.z-dn.net/?f=P%28C%20%5Ccup%20M%29%20%3D%20P%28C%29%2BP%28M%29-P%28C%20%5Ccap%20M%29%5C%5CP%28C%20%5Ccup%20M%29%3D3.23%2B2.4-1.03%5C%5CP%28C%20%5Ccup%20M%29%3D4.6%5C%25)
The probability that a randomly selected can has contamination or a mixing error is 4.6%.
Answer: C = 97.34 inches
Step-by-step explanation:
C = πd
= 3.14(31)
= 97.34
Answer:
A. V= area of base x height 1/3
(20x15)x30x1/3= 3000cm
B.65cm
C.CTCN is the angle between
tan<TCN= TN/NC=12/5
=67.380
D. 10\sqrt(10)
e.tan<TMN=TN/MN=3
<TMN=71.57