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3 years ago

Which pair shows equivalent expressions?

Mathematics

1 answer:

777dan777 [17]3 years ago

5 0

Answer:

3(x + 2) = 3x + 6

Step-by-step explanation:

3(x + 2) = 3x + 6

Distribute --> 3x + 6 = 3x + 6

You might be interested in

Mr. Rivona bought 5 pounds of bananas for $0.45 per pound How much did she spend in all

Alinara [238K]

Answer:

2.25

Step-by-step explanation:

5*.45=2.25

7 0

3 years ago

Pls solve it and show your work :((

lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

To graph the line we need two points, one point is the y-intercept, the second point to be calculated.

y = -3x + 6

The y-intercept is (0, 6)

Let the domain be x = 5 for the second point, then:

y = -3*5 + 6 = -15 + 6 = -9
The point is (5, -9)

Connect these points to get the graph

y = 4/5x - 3

The y-intercept is (0, -3)

Let the domain be x = 5 for the second point, then:

y = 4/5*5 - 3 = 4 - 3 = 1
The point is (5, 1)

Connect these two points to get the graph

5 0

2 years ago

Complete the equation of the lines whose slope is 5 and y-intercept is (0,4) y = ?

Dimas [21]

Answer:

y = 5x + 4

Step-by-step explanation:

y - 4 = 5(x - 0)

That is point-slope form. I'm not sure if you want it in slope intercept form, but slope intercept form of the equation is -

y = 5x + 4

7 0

3 years ago

I hate math i dont understand it help please

Iteru [2.4K]

parallel lines have the same slope

y = 4x-5 the slope is 4

slope intercept form

y= mx+b

the slope is 4 and the y intercept is 3

y = 4x +3

4 0

3 years ago

Read 2 more answers

Help please!!! I dont understand these questions currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago