All categories

3 years ago

Complete the equation of the lines whose slope is 5 and y-intercept is (0,4)y = ?

Mathematics

1 answer:

Dimas [21]3 years ago

7 0

Answer:

y = 5x + 4

Step-by-step explanation:

y - 4 = 5(x - 0)

That is point-slope form. I'm not sure if you want it in slope intercept form, but slope intercept form of the equation is -

y = 5x + 4

You might be interested in

At the Tucson Zoo, Jason spends $6.00 to enter the zoo and $2.00 per animal to feed them. Meanwhile, at the Phoenix Zoo, Kim spe

shtirl [24]

Answer:

3 animals

Step-by-step explanation:

combine like terms

6 + 2x = 15 + x
-6 + x - 6 - x

--------------------------

3x = 9

2. divide both sides by 3

3x/ 3 = 9/3
x = 3

8 0

3 years ago

a class voted for either rollerblading, swimming, or biking as their favorite summer activity. if rollerblading got 21% percent

Sauron [17]

Answer: 39% voted for biking

Step-by-step explanation:

Add the other two percentages and subtract from 100

40 + 21 = 61

100 - 61 = 39

8 0

3 years ago

Theos mom bought an eight pack of juice boxes for 4 dollars find the unit rate

riadik2000 [5.3K]

Answer:

$0.50 for a pack of juice.

Step-by-step explanation:

You are finding the unit rate of the cost of each unit, or one box of juice. In this case, there is 8 juice boxes in the pack, which costs you $4. Divide 4 with 8:

4/8 = 1/2 = 0.5

$0.50 is the cost per pack of juice.

3 0

3 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

3 years ago

PLEASE HELP ASAP!!!<br> solve for the given variable and show your work. 3a-12b=30. solve for b.

olganol [36]

Answer:

b=(-10-a)/4

First factor out the common number:3

Then divide both sides by 3

Then simplify 30/3 to 10

Then subtract a to get your answer

5 0

3 years ago