Answer:
x=5, y=8
Step-by-step explanation:
x+y=13
2x-y=2
add these two equations
3x=15
therefore x=5
apply this value in x+y=13
5+y=13
then y=13-5 = 8
Answer:
. . . . . . . . . . . . .Loading answer. . . . . . . . .
Step-by-step explanation:
* J,K,&L are coplanar
* K is the midpoint of JL
* J,K,&L are collinear
* Jk=KL
Area of a circle = pi*r^2.
Here, A = 380.13 mi. Unfortunately, "mi" is NOT a unit of area.
So I will assume that the problem should read A = 380.13 sq. miles.
380.12 mi^2
Thus, 380.13 mi^2 = 3.14*r^2, and r^2 = ------------------- 121.057 mi^2
3.14
The radius is the sqrt of 121.057 mi^2: 11.00 miles.
The diam. is twice that, or d = 22.00 miles.
The answer is 0, anything divided by 0 automatically cancels out.
