The 11th term is 2, 095, 152
Explanation:
This is a geometric sequence, since each term after the first is obtained by multiplying a common ratio,
r
.
The common ratio is
4
. The first term,
a
, is
2
. The number of terms,
n
is
11
.
We use the formula
t
n
=
a
×
r
n
−
1
to determine the nth term in a geometric sequence.
t
11
=
2
×
4
11
−
1
t
11
=
2
,
095
,
152
Hopefully this helps!
Answer:
The explicit formula is Tn = 18[(2/3)^(n-1)]
Where n is the term we are looking for
Step-by-step explanation:
Here, we want to get an explicit formula to model the equation
Now, F(2) = 2/3 * f1 = 2/3 * 18 = 12
F(3) = 2/3 * f(2) = 2/3 * 12 = 8
F(4) = 2/3 * F(3) = 2/3 * 8 = 16/3
F(5) = 2/3 * 16/3 = 32/9
Thus, seeing how the equations are progressing, we can definitely see a pattern.
That is Tn = (2/3)^(n-1)(18)
Answer:
sometimes
Step-by-step explanation:
If this is an "always, sometimes, never" kind of problem, the answer is sometimes.
An isosceles triangle can be an obtuse triangle sometimes (but might be right or acute. An obtuse triangle can be isosceles or may be scalene. An obtuse triangle cannot be a right triangle nor equilateral.
The names for triangles comes from their angles:
right, acute, obtuse;
OR from their sides:
scalene, isosceles, equilateral.
She can buy 36 sets of cutlery because first you subtract 37.50 from 65 then divide the difference by 0.75.
