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AleksandrR [38]
3 years ago
11

A circle has a diameter of 18 cm. Find the circumference. . Use 3.14 for π.

Mathematics
1 answer:
marta [7]3 years ago
8 0

Answer:

Step-by-step explanation:

C= 2 *3.14*r

we have diameter 2r=d=18

C=18*3.14

C=56.52

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What is the approximate area of the shaded sector in the circle shown below?
viva [34]

Answer:

4.71

Step-by-step explanation:

Area of shaded sector formula: r2(data)(pi)/360

Substitute the info into the formula

3^{2} (60)(pi)/360

9(60)=540

540/360(pi)=4.71

Hope this helps! :)

8 0
3 years ago
Sarah making a square pillow with edges that need to measure 8 inches long. She needs a strip of fabric four times as long as on
Galina-37 [17]

Answer:

The length of the strip of fabric is 32 inches.

Step-by-step explanation:

Consider the provided information.

The length of the edges of the square pillow should be 8 inches.

She needs a strip of fabric four times as long as one of the pillow to make a border around the pillow.

The length of the strip of fabric = 4×8 inches

The length of the strip of fabric = 32 inches

Hence, the length of the strip of fabric is 32 inches.

6 0
3 years ago
Can anyone identify the two variables
valentina_108 [34]
The two variables are time (x) and distance (y)

And the answer is they will meet after 1 mile

The function of the aunt and uncle is y=25x+5

The function of yourself is y2=30x

Since you want to know when you’ll meet, you just resolve y=y2 or 25x+5=30x

Wich will be x=1 so 1 mile
8 0
3 years ago
1/3(-15 divide 1/2) 1/4 what does it equal
Dafna1 [17]

Answer:

-2.5 or - 2 1/2

Step-by-step explanation:

Writing out the expression Mathematically ;

1/3(-15÷1/2)1/4

Using PEMDAS :

Solving the bracket first

(-15 ÷ 1/2) = (-15 * 2/1) = - 30

We have :

1/3(-30)1/4 = - 10 * 1/4 = - 10 / 4 = - 2.5

-2.5 = - 2 1/2

3 0
2 years ago
What is the lateral surface area of a prism
Lesechka [4]

Answer:

The lateral area of a figure is the area of the non-base faces only.

I hope this helps you!

Step-by-step explanation:

3 0
3 years ago
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