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Svetach [21]
2 years ago
10

(7/8x-4) -3 (1/3x+6) HELPP! I have to enter the correct expression!

Mathematics
2 answers:
steposvetlana [31]2 years ago
6 0

Answer:

-1/8x-22

Step-by-step explanation:

Insert 3 in the RHS bracket

Insert - in the RHS bracket

Simplify

Anastasy [175]2 years ago
5 0

Answer:

-\frac{x+176}{8}

Step-by-step explanation:

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The sum of two numbers is 67 . the larger number is 5 more than the smaller number. what are the numbers?
Scorpion4ik [409]
Call the numbers x and y. According to the first sentence, x + y = 67. According to the second sentence, x = y + 5. You can combine these two equations to find the values of these variables:

x + y = 67
(y + 5) + y= 67
2y = 62
y = 31

You can use this to find x by plugging in y to either original equation:

x = y + 5
x = 31 + 5
x = 36
8 0
3 years ago
What is the value of X?<br><br> x=
Sever21 [200]

Answer:

x=12

Step-by-step explanation:

All of the sides are the same length.

5x-22=4x-10=3x+2

5x-22=4x-10

x=12

3 0
3 years ago
2x+15=x/2-3<br><br> Can anyone solve for x?
____ [38]

Answer: X=-12

Right ain’t it ?

3 0
3 years ago
Read 2 more answers
One variable examined is the survival rate 10 years after tagging. The scientists observed that 10 of the 50 metal tagged pengui
Oksana_A [137]

Answer:  90% confidence interval would be (-0.2483,-0.0717)

Step-by-step explanation:

Since we have given that

n₁ = 50

Number of metal tagged penguins survived = 10

So, p_m=\dfrac{10}{50}=0.2

n₂ = 50

Number of electronic tagged penguins = 18

So, p_e=\dfrac{18}{50}=0.36

So, at 90% confidence interval, z = 1.28

So, interval would be

(p_m-p_e)\pm z\sqrt{\dfrac{p_m(1-p_m)}{n}+\dfrac{p_e(1-p_e)}{n}}\\\\=(0.2-0.36)\pm 1.28\sqrt{\dfrac{0.2\times 0.8}{50}+\dfrac{0.36\times 0.64}{50}}\\\\=-0.16\pm 0.0883\\\\=(-0.16-0.0883,-0.16+0.0883)\\\\=(-0.2483,-0.0717)

Hence, 90% confidence interval would be

(-0.2483,-0.0717)

6 0
3 years ago
The values of a sample statistic for different random samples of the same size from the same population will be the same.
Rus_ich [418]

Answer:

In general, sample statistics will tend to be different. With continuous random variables, this should always be the case (until rounding, which brings us back to "actually that's just theoretically continuous") and with discrete random variables this will often be the case with some statistics and perhaps more often not with others (how often it depends on the distribution pattern, sample size, and the particular statistics you are viewing).

Step-by-step explanation:

You can response your particular query by straight experiment, in simple cases.

For example, consider rolling a particular six-sided die (a well-made one that's very close to fair). You could withdraw two samples of some wanted size (n1 = 20

and n2 = 20 say) and calculate your sample statistics. I suggest you try it!

Actually, not being one to ask you to try something I wouldn't do myself, here are my attempts, first with one die (two samples each of size 20) and then a repeat with a different die:

Result of die A: 1 2 3 4 5 6

Sample 1 (Counts) 2 3 3 2 4 6

Sample 2 6 2 3 4 3 2

Result of die B: 1 2 3 4 5 6

Sample 1 (Counts) 3 7 3 0 3 4

Sample 2 1 4 1 5 4 5

And here are some summary statistics:

Die A Range median mean sd

Sample 1 5 4.5 4.05 1,791

Sample 2 5 3 3.10 1,774

Die B Median Mean Range SD

Sample 1 5 2.5 3.25 1,860

Sample 2 5  4  4.10 1,619

If you do, you will probably get the same maximum and minimum both times (I would expect both 1 and 6 to show in a sample of 20 about 95% of the time), but the means and standard deviations would be different.

The medians could be the same (about a 25% chance of that, with the usual definition of sample median even for n

), but easily not.

There is some chance of obtaining the same mean for two of these (because we are sampling a discrete distribution with only a few results), but there is a low probability of seeing it (around 3.7%);

You can also get the same standard deviation, but the chance is much less ... about 2/3 of a percentage.

At larger or smaller sample sizes, those possibilities change; and they change again if you extract from other distributions other than that of a (roughly) fair die.

That all those statistics I mentioned would be the same would be highly unlikely.

3 0
3 years ago
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